最大连续签到天数-sql

 
SELECT   MIN(rq) as 起始日期
 ,   MAX(rq) as 终止日期
 ,  MAX(id1) - MIN(id1) + 1 as 持续天数
 ,id3 as 累计签到天数
 ,name
  
FROM (
 SELECT  datediff(rq,'2020-02-01' )id1
  ,   (
   SELECT COUNT(1)
   FROM tmptable
   WHERE rq <= a.rq and
   type = '是'
  ) id2,
 (
   SELECT COUNT(1)
   FROM tmptable
   WHERE 
   type = '是'
  ) id3,  (
   SELECT MAX(rq)
   FROM tmptable
   WHERE rq < a.rq
   and type = '是'
  ) rq2,rq,type,name
   
 FROM tmptable a
 where type = '是'
) a
GROUP BY a.id1 - a.id2
order by 持续天数  desc
limit 1
 

SELECT   MIN(rq) as 本期起始日期
 ,   MAX(rq) as 本期终止日期
 ,  MAX(id1) - MIN(id1) + 1 as 持续天数
 ,    CASE a.id1 - a.id2  
  WHEN -1 THEN 0
  ELSE MAX(datediff( rq2, rq))
 END as 距上一期天数
FROM (
 SELECT  datediff(rq,'2020-02-01' )id1
  ,   (
   SELECT COUNT(1)
   FROM tmptable
   WHERE rq <= a.rq and
   type = '是'
  ) id2,  (
   SELECT MAX(rq)
   FROM tmptable
   WHERE rq < a.rq
   and type = '是'
  ) rq2,rq,type,name
   
 FROM tmptable a
 where type = '是'
) a
GROUP BY a.id1 - a.id2