杭电 hdu 1800 Flying to the Mars (水题 STL)

杭电  hdu  1800    Flying to the Mars  (水题   STL)



Flying to the Mars

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 13290    Accepted Submission(s): 4218


Problem Description

In the year 8888, the Earth is ruled by the PPF Empire . As the population growing , PPF needs to find more land for the newborns . Finally , PPF decides to attack Kscinow who ruling the Mars . Here the problem comes! How can the soldiers reach the Mars ? PPF convokes his soldiers and asks for their suggestions . “Rush … ” one soldier answers. “Shut up ! Do I have to remind you that there isn’t any road to the Mars from here!” PPF replies. “Fly !” another answers. PPF smiles :“Clever guy ! Although we haven’t got wings , I can buy some magic broomsticks from HARRY POTTER to help you .” Now , it’s time to learn to fly on a broomstick ! we assume that one soldier has one level number indicating his degree. The soldier who has a higher level could teach the lower , that is to say the former’s level > the latter’s . But the lower can’t teach the higher. One soldier can have only one teacher at most , certainly , having no teacher is also legal. Similarly one soldier can have only one student at most while having no student is also possible. Teacher can teach his student on the same broomstick .Certainly , all the soldier must have practiced on the broomstick before they fly to the Mars! Magic broomstick is expensive !So , can you help PPF to calculate the minimum number of the broomstick needed .
For example : 
There are 5 soldiers (A B C D E)with level numbers : 2 4 5 6 4;
One method :
C could teach B; B could teach A; So , A B C are eligible to study on the same broomstick.
D could teach E;So D E are eligible to study on the same broomstick;
Using this method , we need 2 broomsticks.
Another method:
D could teach A; So A D are eligible to study on the same broomstick.
C could teach B; So B C are eligible to study on the same broomstick.
E with no teacher or student are eligible to study on one broomstick.
Using the method ,we need 3 broomsticks.
……

After checking up all possible method, we found that 2 is the minimum number of broomsticks needed. 
 

Input
Input file contains multiple test cases. 
In a test case,the first line contains a single positive number N indicating the number of soldiers.(0<=N<=3000)
Next N lines :There is only one nonnegative integer on each line , indicating the level number for each soldier.( less than 30 digits);
 

Output
For each case, output the minimum number of broomsticks on a single line.
 

Sample Input
 
   
4 10 20 30 04 5 2 3 4 3 4
 

Sample Output
 
   
1 2
 

Author
PPF@JLU
 

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题意:给出很多组数字,每一个从小到大的序列算一队,问最少可以组成多少队




题解: 其实每次都减去最长的上升序列,最后留下的还是重复的数字,所以只需要求出这一串数字中最多的相同数字就可以了
所以可以用开数组,或者用map,其实最好还是用map防止中间有空隙从而浪费空间



#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 

using namespace std;

int main ()
{
    int ch;
    int n, i;

    while (scanf ("%d", &n) != EOF)
    {
        mapmp;                 //创建map
        map::iterator iter;     //迭代器
        for (i = 1; i <= n; ++i)
        {
            scanf ("%d", &ch);
            mp[ch]++;                          //将相同的数字计数
        }
        int sum = 0;
        for (iter = mp.begin(); iter != mp.end(); ++iter)          //遍历一次,找出最多的数字
        {
            if (iter->second > sum)
                sum = iter->second;
        }
        cout<




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