Codeforces Beta Round #49 (Div. 2)-C. Little Frog

C. Little Frog
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

Once upon a time a little frog whose name was Vasya decided to travel around his home swamp. Overall there are n mounds on the swamp, located on one line. The distance between the neighboring mounds is one meter. Vasya wants to visit all the mounds in one day; besides, he wants to visit each one exactly once. For that he makes a route plan, to decide the order in which to jump on the mounds. Vasya can pick any mound as the first one. He thinks it boring to jump two times at the same distance. That's why he wants any two jumps on his route to have different lengths. Help Vasya the Frog and make the plan for him.

Input

The single line contains a number n (1 ≤ n ≤ 104) which is the number of mounds.

Output

Print n integers pi (1 ≤ pi ≤ n) which are the frog's route plan.

  • All the pi's should be mutually different.
  • All the |pipi + 1|'s should be mutually different (1 ≤ i ≤ n - 1).

 

If there are several solutions, output any.

Sample test(s)
input
2
output
1 2 
input
3
output
1 3 2 
水题:只需前后交替输出
 1 /******************************
 2 AC
 3 date£º2013-10-9-17:00
 4 *********************************/
 5 
 6 
 7 #include 
 8 #include
 9 #include<string.h>
10 #include
11 
12 using namespace std;
13 
14 int main()
15 {
16     int n;
17     scanf("%d",&n);
18     int i;
19     for(i=1;i<=n/2;i++)
20     {
21         if(i==(int)(n/2))
22         printf("%d %d",i,n-i+1);
23         else
24         printf("%d %d ",i,n-i+1);
25     }
26     if(n%2==0)
27     printf("\n");
28     else if(n==1)
29     printf("1\n");
30     else
31     printf(" %d\n",n/2+1);
32     return 0;
33 }
View Code

 



转载于:https://www.cnblogs.com/ACshasow/p/3362106.html

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