2048这个游戏相信好多人都玩过,想想其实功能挺简单的,无非就是上下左右移动,然后判断数字,接着随机出现2或者4。
原来我是我用好多函数实现的,显得有点乱。然后看到别人用类实现,创建对象,调用成员函数,感觉写的非常好,借鉴了好多地方改了改。
1. 我们先来看看主函数:
int main()
{
unsigned int x = 1, y = 1;
while (x == y)
{
srand((unsigned)time(NULL));
x = rand() % 16;
y = rand() % 16;
}
Array a(x, y);
cout << a;
char c;
while (c=_getch())
{
bool flag = false;
switch (c)
{
case 'w':
flag = a.moveUp();
break;
case 's':
flag = a.moveDown();
break;
case 'a':
flag = a.moveLeft();
break;
case 'd':
flag = a.moveRight();
break;
default:
break;
}
if (flag)
{
a.upDate();
system("cls");
cout << a;
}
if (a.checkGame())
{
cout << endl;
cout << " **********************" << endl;
cout << " 小 game over! 妖" << endl;
cout << " 小 拜拜 妖" << endl;
cout << " **********************" << endl;
Sleep(10000);
return 0;
}
}
return 0;
}
a. 上面的x 和y是为了启动游戏时随机位置出现2。
b. 重载了输出符<<.
c. 然后就是上下左右移动了,为了方便判断是否执行成功,我们用bool类型作为这些函数的返回值。
d. checkGame()是一个检查游戏是否结束的函数。
2.我们看看这几个函数怎么实现的。
Array::Array(int x1, int x2)
{
int* p = &m_num[0][0];//定义一个指针,指向数组的首地址
memset(m_num, 0, sizeof(m_num));//初始化数组,memset用法:memset(数组名,初始化数字,数组大小)
*(p + x1) = 2;//刚运行程序后出现的两个数字
*(p + x2) = 2;
}
bool Array::checkGame()
{
bool flag = true;
unsigned int i, j;
for (i = 0; i < 3; i++)
{
for (j = 0; j < 3; j++)
{
if (m_num[i][j] == 0 || m_num[i][3] == 0 || m_num[3][i] == 0 || m_num[3][3]==0
|| m_num[i][j] == m_num[i][j + 1] || m_num[j][i] == m_num[j + 1][i]
|| m_num[i][3]==m_num[i+1][3] || m_num[3][i]==m_num[3][i+1])
{
flag = false;
return flag;
}
}
}
return flag;
}
bool Array::moveUp()
{
unsigned int i, j, k, m;
int temp[4][4];
bool flag = false;
for (i = 0; i < 4; i++)
{
for (j = 0; j < 4; j++)
{
temp[i][j] = m_num[i][j];
}
}
for (i = 0; i < 4; i++)//每行四个数字
{
for (k = 0; k < 3; k++)//若是将下一行的数字为0,移动上去后,还是0,所以要每行都再次比较一下
{
for (j = 0; j < 3; j++)//上下比较三个数字
{
if (m_num[j][i] == 0)
{
for (m = j; m < 3; m++)
{
m_num[m][i] = m_num[m + 1][i];//第N行时,将下面的几行向上移动一次
}
m_num[3][i] = 0;//最后一行赋值0
}
}
}
}
for (i = 0; i < 4; i++)
{
for (j = 0; j < 3; j++)//上下比较三个数字
{
if (m_num[j][i] == m_num[j + 1][i])
{
m_num[j][i] += m_num[j + 1][i];
for (m = j + 1; m < 3; m++)//下下一行向上移动
{
m_num[m][i] = m_num[m + 1][i];
}
m_num[3][i] = 0;//最后一行赋值0
}
}
}
for (i = 0; i < 4; i++)
{
for (j = 0; j < 4; j++)
{
if (temp[i][j] != m_num[i][j])//移动后和以前的数字不一样,证明还能移动
{
flag = true;
return flag;
}
}
}
return flag;
}
(上下左右移动的函数差不多,只改几个数字而已,这里仅列出向上移动的函数)
bool Array::addNum(int i)
{
bool flag = false;
int *p = &m_num[0][0];
if (*(p + i) == 0)
{
srand((unsigned)time(NULL));
int x = rand() % 4;//此处定义出现2和4的概率,我定义为1:4
if (x == 1)
*(p + i) = 4;
else
*(p + i) = 2;
flag = true;
}
return flag;
}
ostream& operator<<(ostream& is, const Array& array)
{
is << " 上(w) 下(s) 左(a) 右(d) " << endl;
is << "-----------------------------" << endl;
for (unsigned int i = 0; i < 4; i++)
{
for (unsigned int j = 0; j < 4; j++)
{
is << "|" << setw(6);
if (array.m_num[i][j] != 0)
is << array.m_num[i][j];
else
is << " ";
}
is << "|" << endl;
for (unsigned int j = 0; j < 4; j++)
{
is << "|" << setw(6) << " ";
}
is << "|" << endl;
is << "-----------------------------" << endl;
}
return is;
}