发帖水王

关于发帖水王的求解，第一种解法是编程之美上的解法，第二种解法是寻找中位数，因为中位数必然超过一半，两种解法这里不再做解答

扩展问题很好，有3个发帖很多的ID，他们的发帖数量都超过了帖子总数目N的1/4，找出他们的ID

#include 

using namespace std;

int array[] = {1, 2, 1, 1, 2, 3, 2, 2, 3, 3, 1, 3, 4, 5, 6};
const int size = sizeof array / sizeof *array;

bool is_Error = false;

int getShuiWang(int *array, int size)
{
	if (array == NULL || size <= 0)
	{
		is_Error = true;
		return -1;
	}

	const int number = 3;
	int candidate[number];
	int times[number];

	for (int i = 0; i < number; i++)
	{
		times[i] = 0;
	}

	for (int i = 0; i < size; i++)
	{
		bool is_In = false;
		for (int j = 0; j < number; j++)
		{
			if (times[j] != 0)
			{
				if (candidate[j] == array[i])
				{
					times[j]++;
					is_In = true;
					break;
				}
			}
		}
		if (is_In == true)
			continue;

		is_In = false;
		for (int j = 0; j < number; j++)
		{
			if (times[j] == 0)
			{
				candidate[j] = array[i];
				times[j] = 1;
				is_In = true;
				break;
			}
		}
		if (is_In == true)
			continue;

		for (int j = 0; j < number; j++)
		{
			times[j]--;
		}
	}

	for (int i = 0; i < number; i++)
		cout << candidate[i] << endl;

	return 0;
}

void main()
{
	int result = getShuiWang(array, size);
	cout << "result = " << result << endl;
	//return;
}