NEON函数详解------vld3_8、vst3_u8

#include
#include "stdio.h"

int main (void)
{
    int i;
    uint8x8x3_t v; // This represents 3 vectors.
   // Each vector has eight lanes of 8-bit data.

    unsigned char A[24]={1,1,1,

                                           2,1,1,
                                           3,1,1,
                                           4,1,1,
                                           5,1,1,
                                           6,1,1,
                                           7,1,1,

                                           8,1,1}; // This array represents a 24-bit RGB image.

v = vld3_u8(A); // This de-interleaves the 24-bit image from array A

//Double the red channel

v.val[0] = vadd_u8(v.val[0],v.val[0]);

vst3_u8(A, v); // store the vector back into the array, with the red channel doubled.

    for(i=0;i<24;i++)

    printf("%d ",A[i]);

    printf("\n");

  

    return 0;

}

~                                                                                                                                                                                                            结果：      2 1 1

                    4 1 1

                    6 1 1

                    8 1 1

                   10 1 1

                   12 1 1

                   14 1 1

                   16 1 1

 

~          

#include
#include "stdio.h"

int main (void)
{
int i;
uint16x4x3_t v; // This represents 3 vectors.
// Each vector has eight lanes of 8-bit data.
unsigned short A[12]={1,1,1,
                     1,1,1,
                     1,1,1,
                     1,1,1
                         }; // This array represents a 24-bit RGB image.
v = vld3_u16(A); // This de-interleaves the 24-bit image from array A
//Double the red channel
v.val[0] = vadd_u16(v.val[0],v.val[0]);
vst3_u16(A, v); // store the vector back into the array, with the red channel doubled.

    for(i=0;i<12;i++)

    printf("%d ",A[i]);

    printf("\n");
return 0;
}

 结果：       2 1 1 2 1 1 2 1 1 2 1 1