hdu4614

删除操作很好解决，主要难点在于插入操作如何确定插入位置，用二分查找来解决 

#include 
#include
#include
using namespace std;
const int N = 50005;
int n,m;
struct node
{
    int sum,lazy;
}tree[N<<2];
 
void build(int num,int s,int e)
{
    tree[num].sum = 0;
    tree[num].lazy = -1;
    if(s == e)
        return;
    int mid = (s + e)>>1;
    build(num<<1,s,mid);
    build(num<<1|1,mid + 1,e);
}
 
void pushup(int num)
{
    tree[num].sum = tree[num<<1].sum + tree[num<<1|1].sum;
}
 
void pushdown(int num,int s,int e)
{
    tree[num<<1].lazy = tree[num<<1|1].lazy = tree[num].lazy;
    if(tree[num].lazy)
    {
        int mid = (s + e)>>1;
        tree[num<<1].sum = mid - s + 1;
        tree[num<<1|1].sum = e - mid;
    }
    else
        tree[num<<1].sum = tree[num<<1|1].sum = 0;
    tree[num].lazy = -1;
}
 
void update(int num,int s,int e,int l,int r,int val)
{
    if(s == l && r == e)
    {
        tree[num].lazy = val;
        if(val)
            tree[num].sum = e - s + 1;
        else
            tree[num].sum = 0;
        return;
    }
    if(tree[num].lazy > -1)
        pushdown(num,s,e);
    int mid = (s + e)>>1;
    if(r <= mid)
        update(num<<1,s,mid,l,r,val);
    else
    {
        if(l > mid)
            update(num<<1|1,mid + 1,e,l,r,val);
        else
        {
            update(num<<1,s,mid,l,mid,val);
            update(num<<1|1,mid + 1,e,mid + 1,r,val);
        }
    }
    pushup(num);
}
 
int query(int num,int s,int e,int l,int r)
{
    if(s == l && e == r)
        return tree[num].sum;
    if(tree[num].lazy > -1)
        pushdown(num,s,e);
    int mid = (s + e)>>1;
    if(r <= mid)
        return query(num<<1,s,mid,l,r);
    else
    {
        if(l > mid)
            return query(num<<1|1,mid + 1,e,l,r);
        else
            return query(num<<1,s,mid,l,mid) + query(num<<1|1,mid + 1,e,mid + 1,r);
    }
}
 
int bin(int s,int rank)//rank:需要插入的花的数目
{
    int l = s;
    int r = n;
    int ans = -1;
    int mid;
    while(l <= r)
    {
        int mid = (l + r)>>1;
        int tmp = query(1,1,n,s,mid);
        if(tmp + rank == mid - s + 1)
        {
            ans = mid;
            r = mid - 1;
        }
        else
        {
            if(tmp + rank < mid - s + 1)
                r = mid - 1;
            else
                l = mid + 1;
        }
    }
    return ans;
}
 
int main()
{
    int i,t;
    int op,a,b;
    scanf("%d",&t);
    while(t --)
    {
        scanf("%d%d",&n,&m);
        build(1,1,n);
        while(m --)
        {
            scanf("%d%d%d",&op,&a,&b);
            if(op == 1)
            {
                int st,ed;
                a ++;
                st = bin(a,1);
                if(st == -1)
                    puts("Can not put any one.");
                else
                {
                    int tmp = query(1,1,n,st,n);
                    tmp = n - st + 1 - tmp;
                    if(tmp <= b)
                        b = tmp;
                    ed = bin(a,b);
                    printf("%d %d\n",st - 1,ed - 1);
                    update(1,1,n,st,ed,1);
                }
            }
            else
            {
                a ++;b ++;
                printf("%d\n",query(1,1,n,a,b));
                update(1,1,n,a,b,0);
            }
        }
        puts("");
    }
    return 0;
}