LeetCode0844. 比较含退格的字符串

一. 题目

1. 题目
   

2. 示例
   

二. 方法一: 无脑暴力法

1. 解题思路

2. 解题代码

   def backspaceCompare(self, S: str, T: str) -> bool:
       str1 = ""
       str2 = ""
       for ele in S:
           if ele != "#":
               str1 += ele
           else:
               str1 = str1[0: -1]
       for ele in T:
           if ele != "#":
               str2 += ele
           else:
               str2 = str2[0: -1]
       if str1 == str2:
           return True
       return False
   

3. 分析