[杂项项目]纯C语言实现控制台小游戏——数字拼图

一年前写的小游戏，当时感觉小有成就，现在发现缺陷真的很多。不禁感叹，当时为什么会用那么多goto呢。在这里真的建议大家不要用goto。只是现在懒得改了，毕竟是小程序。贴出来供大家参考。如果有时间后序再添加注释。如有问题欢迎评论。

#include 
#include 
#include
#include 
#define max 10
int x, y, step, label = 0;
typedef struct score {
	int steps, steps2;
	double times;
	char name[18];
}score;
score sco[max + 1];
char ch, buff[3];
bool flag, flag1 = false;
clock_t start, finish;
bool over(){
	system("cls");
	printf("\n\n\n\n\t\t\t您共用了 %d 步 ,耗时 %.3f 分钟\n", step, (double)(finish - start) / 40000);
	system("pause");
	system("cls");
	printf("\n\n\n\n\n\n\n\n\t*******************  您是否重新开始游戏 (Y/N) ?  *******************\n\n");
	scanf("%s", buff);
	ch = buff[0];
	if (ch != 'n'&&ch != 'N') {
		return false;
	}
	else {
		printf("\n\n\n\n\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n");
		printf("\t+++++++++++++++++++++++++   感谢您的使用   +++++++++++++++++++++++++\n", step);
		        printf("\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n\n");
		system("pause");
		exit(0);
	}
	return true;
}
void rank(score sco[],int n) {
	int i, j;
	sco[0] = sco[n];
	for (i = 0; i < n; i++)
		if (sco[n].steps2>sco[i].steps2) {
			for (j = n; j > i; j--)
				sco[j] = sco[j - 1];
			sco[i] = sco[0];
			break;
		}
	for (j = i - 1; j > 0; j--)
		if (sco[i].steps2 == sco[j].steps2&&sco[i].steps < sco[j].steps)
			sco[0] = sco[i], sco[i] = sco[j], sco[j] = sco[0], i = j;
		else if (sco[i].steps2 == sco[j].steps2&&sco[i].steps == sco[j].steps)
			if (sco[i].times < sco[j].times)
				sco[0] = sco[i], sco[i] = sco[j], sco[j] = sco[0], i = j;
}
int check2(int *p, int n) {
	int i, j, flag2 = 0;
	for (i = 1; i < n*n - 1; i++) 
		for (j = 0; j < i; j++) 
			if (p[j] > p[i])
				flag2++;
	if (!flag2)
		return 0;
	else if (flag2 % 2 == 0)
		return 2;
	else
		return 1;
}
bool check(int *p,int n) {
	int i;
	flag = true;
	for (i = 0; i= 'a'&&ch <= 'z')
		ch -= 32;
	switch (ch) {
	case 'A': if (y == n - 1) return 1;
		p[x*n + y] = p[x*n + y + 1];
		p[x*n + y + 1] = 0;
		y++;
		step++;
		return 1;
	case 'W': if (x == n - 1) return 1;
		p[x*n + y] = p[(x + 1)*n + y];
		p[(x + 1)*n + y] = 0;
		x++;
		step++;
		return 1;
	case 'D': if (y == 0) return 1;
		p[x*n + y] = p[x*n + y - 1];
		p[x*n + y - 1] = 0;
		y--;
		step++;
		return 1;
	case 'S': if (x == 0) return 1;
		p[x*n + y] = p[(x - 1)*n + y];
		p[(x - 1)*n + y] = 0;
		x--;
		step++;
		return 1;
	case 'R': return 2;
	case 'M': return 3;
	case 'Q': printf("\n\n\t********************* 您是否要离开游戏 (Y/N) ? *********************\n\n");
		scanf("%s", buff);
		ch = buff[0];
		if (ch == 'y' || ch == 'Y')
			return 4;
		else
			return 1;
	default: return 1;
	}
	return 0;
}
void map(int *p, int n) {
	int i, j;
	system("cls");
	printf("\n\n\n");
	for (i = 0; i < n; i++)
	{
		printf("\t");
		for (j = 0; j < n; j++)
		{
			if (p[n*i + j] != 0)
				printf("%-4d", p[n*i + j]);
			else
				printf("    ");
		}
		printf("\n\n");
	}
	printf("\n\t按方向键移动卡片至无卡片的地方  W:上 S:下 A:左 D:右 M:返回菜单 R:换图 Q:退出\n\n");
	finish = clock();
	printf("\n\t\t\t\t步数: %d\t 使用时间: %.3f 分钟 \n\n", step, (double)(finish - start) / 40000);
}
void reset(int *p, int n) {
	int i, j, flag2;
	system("cls");
	do {
		for (i = 0; i < n*n - 1; i++) {
			do {
				flag2 = 1;
				p[i] = rand() % (n*n - 1) + 1;
				for (j = 0; j < i; j++)
					if (p[i] == p[j])
						flag2 = 0;
			} while (!flag2);
		}
		flag2 = check2(p, n);
		if (flag2 == 1) {
			flag2 = p[n*n - 2];
			p[n*n - 2] = p[n*n - 3];
			p[n*n - 3] = flag2;
		}
	} while (!flag2);
	p[n*n - 1] = 0;
	for (i = 0; i 1)
			p = (int*)calloc(n*n, sizeof(int));
		else
			printf("\t********************** 您输入有误，请重新输入 **********************\n\n"), system("pause");
	} while (n <= 1);
next1:
	step = 0;
	start = clock();
	reset(p, n);
next2:
	map(p, n);
	if (check(p, n) == false) {
		printf("\n\n\t=================+ 恭喜您完成游戏，请输入您的姓名 +=================\n\n");
		scanf("%s", sco[++label].name);
		sco[label].steps = step;
		sco[label].steps2 = n;
		sco[label].times = (double)(finish - start) / 40000;
		rank(sco, label);
		if (over() == false)
			return;
	}
	mark = operation(p, n);
	if (mark == 1)
		goto next2;
	else if (mark == 2)
		goto next1;
	else if (mark == 3)
		return;
	else if (mark == 4)
		if (over() == false)
			return;
	free(p);
}
int main(){
	srand((int)time(0));	
	do {
		system("cls");
		printf("\t-------------+ 欢迎来到浅悠悠数字拼图，请选择您的操作 +-------------\n\n");
		printf("\t-----+  1.开始游戏  +-----+  2.帮助  +-----+  0(或其他).退出  +-----\n\n");
		printf("\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n\n");
		scanf("%s", buff);
		ch = buff[0];
		switch (ch){
		case'1':
			game(); break;
		case'2':
			help(); break;
		case'0':
			exit(0);
		default:
			exit(0);
		}
	} while (ch != '0');
	return 0;
}