介值定理。很短但很有用。
Since f f f is a continuous function on [ a , b ] [a,b] [a,b], by the maximum principle, there’s x 1 , x 2 ∈ [ a , b ] x_1,x_2∈[a,b] x1,x2∈[a,b] such that
M = f ( x 1 ) , m = f ( x 2 ) M=f(x_1 ),\quad m=f(x_2 ) M=f(x1),m=f(x2)
If x 1 = x 2 x_1=x_2 x1=x2, then let c = x 1 c=x_1 c=x1 and the proof is over, assume x 1 < x 2 x_1
We let F ( x ) = f ( x ) − x F(x)=f(x)-x F(x)=f(x)−x, by Proposition 9.4.9 and Exercise 9.4.6, F ( x ) F(x) F(x) is continuous on [ 0 , 1 ] [0,1] [0,1], since f f f has range [ 0 , 1 ] [0,1] [0,1], we know that f ( 0 ) ≥ 0 f(0)≥0 f(0)≥0 and f ( 1 ) ≤ 1 f(1)≤1 f(1)≤1, thus
F ( 0 ) = f ( 0 ) ≥ 0 , F ( 1 ) = f ( 1 ) − 1 ≤ 0 F(0)=f(0)≥0,\quad F(1)=f(1)-1≤0 F(0)=f(0)≥0,F(1)=f(1)−1≤0
Since F ( 0 ) ≥ 0 ≥ F ( 1 ) F(0)≥0≥F(1) F(0)≥0≥F(1), by the Intermediate value theorem, there exists c ∈ [ 0 , 1 ] c∈[0,1] c∈[0,1] such that F ( c ) = 0 F(c)=0 F(c)=0, or f ( c ) = c f(c)=c f(c)=c, this is the fixed point we search for.