Ajax异步提交登录(2)--登录使用

 

http://cjp1989.iteye.com/blog/1740964

 

1.Ajax的原理： Ajax的原理就是:通过javascript的方式，将前台数据通过xmlhttp对象传递到后台，后台在接收到请求后，将需要的结果，再传回到前台，这样就可以实现不需要页面的转发，数据实现来回传递，从而实现页面无刷新。 基于这个原理，我想到使用Ajax传输登录的信息，包括错误信息，功能很强大，保证绝对的用户友好型。 
2.使用Ajax异步提交登录可以实现功能：可以提示用户名错误，可以提示用户名正确但是密码不正确...等等一切错误信息。保证绝对的友好型。绝对的好用！！！ 
下面附上我的简单操作....可以任读者扩展.... 

 
       
         </li> 
       <li>    function login(){  </li> 
       <li>        var username=document.getElementById(<span class="string">"username");  </span></li> 
       <li>        var password=document.getElementById(<span class="string">"password");  </span></li> 
       <li>        <span class="keyword">if(username.value==<span class="string">""){  </span></span></li> 
       <li>            alert(<span class="string">"请输入用户名...");  </span></li> 
       <li>            username.focus();  </li> 
       <li>            <span class="keyword">return;  </span></li> 
       <li>        }  </li> 
       <li>        <span class="keyword">if(password.value==<span class="string">""){  </span></span></li> 
       <li>            alert(<span class="string">"请输入密码...");  </span></li> 
       <li>            password.focus();  </li> 
       <li>            <span class="keyword">return;  </span></li> 
       <li>        }  </li> 
       <li>        <span class="keyword">else{  </span></li> 
       <li>            $.ajax({  </li> 
       <li>                url:<span class="string">'login.action',  </span></li> 
       <li>                data:<span class="string">'username='+username.value+<span class="string">'&password='+password.value+<span class="string">'',   </span></span></span></li> 
       <li>                success:function(msg){  </li> 
       <li>                   var data=msg;  </li> 
       <li>                    <span class="keyword">if(<span class="number">0<data.length&&data.length<<span class="number">10){  </span></span></span></li> 
       <li>                        document.getElementById(<span class="string">"msg").innerHTML=<span class="string">'<span style="color:red;font-size:14px">'+  </span></span></li> 
       <li>                        data+<span class="string">'...<a href="#" style="color:blue;font-size:14px" οnclick="location.reload()">请重新登录</a></span><br></br>';  </span></li> 
       <li>                    }<span class="keyword">else{  </span></li> 
       <li>        document.form1.action=<span class="string">"*****.action"              </span></li> 
       <li>                      document.form1.submit();  </li> 
       <li>                    }  </li> 
       <li>                },  </li> 
       <li>                error:function(){  </li> 
       <li>                    alert(<span class="string">"登录验证失败...请刷新页面重新登录...");  </span></li> 
       <li>                }  </li> 
       <li>            });  </li> 
       <li>        }  </li> 
       <li>    }  </li> 
       <li>
  </li> 
       <li>    function login(){  </li> 
       <li>        var username=document.getElementById(<span class="string">"username");  </span></li> 
       <li>        var password=document.getElementById(<span class="string">"password");  </span></li> 
       <li>        <span class="keyword">if(username.value==<span class="string">""){  </span></span></li> 
       <li>            alert(<span class="string">"请输入用户名...");  </span></li> 
       <li>            username.focus();  </li> 
       <li>            <span class="keyword">return;  </span></li> 
       <li>        }  </li> 
       <li>        <span class="keyword">if(password.value==<span class="string">""){  </span></span></li> 
       <li>            alert(<span class="string">"请输入密码...");  </span></li> 
       <li>            password.focus();  </li> 
       <li>            <span class="keyword">return;  </span></li> 
       <li>        }  </li> 
       <li>        <span class="keyword">else{  </span></li> 
       <li>            $.ajax({  </li> 
       <li>                url:<span class="string">'login.action',  </span></li> 
       <li>                data:<span class="string">'username='+username.value+<span class="string">'&password='+password.value+<span class="string">'',   </span></span></span></li> 
       <li>                success:function(msg){  </li> 
       <li>                   var data=msg;  </li> 
       <li>                    <span class="keyword">if(<span class="number">0<data.length&&data.length<<span class="number">10){  </span></span></span></li> 
       <li>                        document.getElementById(<span class="string">"msg").innerHTML=<span class="string">'<span style="color:red;font-size:14px">'+  </span></span></li> 
       <li>                        data+<span class="string">'...<a href="#" style="color:blue;font-size:14px" οnclick="location.reload()">请重新登录</a></span><br></br>';  </span></li> 
       <li>                    }<span class="keyword">else{  </span></li> 
       <li>        document.form1.action=<span class="string">"*****.action"              </span></li> 
       <li>                      document.form1.submit();  </li> 
       <li>                    }  </li> 
       <li>                },  </li> 
       <li>                error:function(){  </li> 
       <li>                    alert(<span class="string">"登录验证失败...请刷新页面重新登录...");  </span></li> 
       <li>                }  </li> 
       <li>            });  </li> 
       <li>        }  </li> 
       <li>    }  </li> 
       <li>

转载于:https://www.cnblogs.com/LuoEast/p/6817393.html