led点阵操作方式

以一个8X8点阵为例子：

循环将行信号线的每一位置0（COL）：

unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};

行信号线0每移动一次列信号就跟着换一次编码（ROW）：

unsigned char code digittab[18][8]={
{0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00}, //0
{0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00}, //1
{0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00}, //2
{0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00}, //3
{0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00}, //4
{0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00}, //5
{0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00}, //6
{0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00}, //7
{0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00}, //8
{0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00}, //9
{0x00,0x00,0x7F,0x48,0x48,0x30,0x00,0x00}, //P
{0x00,0x00,0x7F,0x48,0x4C,0x73,0x00,0x00}, //R
{0x00,0x00,0x7F,0x49,0x49,0x49,0x00,0x00}, //E
{0x00,0x00,0x3E,0x41,0x41,0x62,0x00,0x00}, //C
{0x00,0x00,0x7F,0x08,0x08,0x7F,0x00,0x00}, //H
{0x00,0x00,0x00,0xFF,0xFF,0x00,0x00,0x00}, //I
{0x00,0x7F,0x10,0x08,0x04,0x7F,0x00,0x00}, //N
{0x7C,0x48,0x48,0xFF,0x48,0x48,0x7C,0x00}  //中
};

void main(void)
{
cnty = 0;
unsigned char cntx , cnty ;
while(1)
{ 
if(cnty < 18) //红色
{
P1 = 0xFF;
P2 = tab[cntx];  // 列线
P0 = digittab[cnty][cntx];   // 行线
}
else //绿色
{
P2 = 0xFF;
P1 = tab[cntx];   // 列线
P0 = digittab[cnty-18][cntx];// 行线
}

//用于控制动态扫描的速度，条件判断语句执行，不满足的情况下，相当于延时一段时间
if(++timecount1 >= 50)
{
timecount1 = 0;
if(++cntx >= 8) 
cntx = 0;
}

//用于控制动字符间的切换速度，条件判断语句执行，不满足的情况下，相当于延时一段时间
if(++timecount2 >= 20000)
{
timecount2 = 0;
if(++cnty >= 36)
cnty = 0;
}
}
}