srm 308 div2 1000（DP, 离散背包+连续背包）

题意：
n个背包，有的可以拆分，有的不能拆。给定Weight求最大值。
思路：
离散和连续的分别求一下。然后枚举i，W-i

class TreasuresPacking
{
        public:
        double maximizeCost(vector <string> treasures, int W)
        {
        vector dis, con;
        for (int i=0;istringstream ss;ss << treasures[i];
            int w, v;char flag;
            ss >> w >> v >> flag;
            if (flag == 'Y') {
                con.push_back( (node) {w, v} );
            }
            else
                dis.push_back( (node) {w, v} );
        }
        sort(con.begin(), con.end(), comp);
        vector<double> fcon(W+1);
        int sum = 0, ok = 1;
        for (int i=0;idouble f = con[i].v*1.0/con[i].w;
            for (int j=0;jif (sum > W) {
                    ok = 0;break;
                }
                fcon[sum] = fcon[sum-1] + f;
            }
        }
        vector<int> fdis(W+1);
        for (int i=0;ifor (int j=W;j>=dis[i].w;--j)
                fdis[j] = max (fdis[j], fdis[j-dis[i].w] + dis[i].v);
        double ans = 0;
        for (int i=0;i<=W;++i) ans = max (ans, fdis[i] + fcon[W - i]);
        return ans;
        }
};