CFF认证考试 2019-09-1 小明种苹果(C++版本)

201909-1
小明种苹果
CFF认证考试 2019-09-1 小明种苹果(C++版本)_第1张图片

#include
#include
using namespace std;

int main()
{
	int treenum, surveynum;              //苹果树个数和疏果操作次数
	int i, j;
	int all = 0, number = 0, drop = 0;       //存放输出结果——剩余总苹果量、最大疏果量所在树的编号、最大疏果量
	cin >> treenum >> surveynum;

	int **array;                 //每一行都存放单颗苹果树总苹果量和每轮疏果量
	array = new int*[treenum];
	for (i = 0; i < treenum; i++)
		array[i] = new int[surveynum + 1];

	for (i = 0; i < treenum; i++)
		for (j = 0; j <= surveynum; j++)
			cin >> array[i][j];

	for (i = 0; i < treenum; i++)
		for (j = 0; j <= surveynum; j++)
			all = all + array[i][j];

	vector<vector<int>> p(treenum,vector<int>(2));   //定义treenum行、两列的vector
	for (i = 0; i < treenum; i++)    //存放每棵苹果树的编号及其疏果总量
	{
		p[i][0] = i + 1;
		for (j = 1; j <= surveynum; j++)
		{
			p[i][1] = p[i][1] + array[i][j];
		}
	}

	for (i = treenum - 1; i > 0; i--)          //将p按照疏果量由大到小排序
		for (j = 0; j <= i - 1; j++)
		{
			int temp1 = 0, temp2 = 0;
			if (-(p[j][1]) < -(p[i][1]))
			{
				temp1 = p[j][1];
				p[j][1] = p[i][1];
				p[i][1] = temp1;
				temp2 = p[j][0];
				p[j][0] = p[i][0];
				p[i][0] = temp2;
			}
		}
	
	drop = -(p[0][1]);
	number = p[0][0];
	for (i = 0; p[i][1] == p[i + 1][1]; i++)   //保证最大疏果量对应的苹果树编号最小
		if (number > p[i + 1][0])
			number = p[i + 1][0];
	cout << all << " " << number << " " << drop << endl;

	delete []array;
	return 0;
}

在这里插入图片描述
该代码没有完美得分,望大神们指点,谢谢

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