jdk8新特性-亮瞎眼的lambda表达式

jdk8之前,尤其是在写GUI程序的事件监听的时候,各种的匿名内部类,大把大把拖沓的代码,程序毫无美感可言!既然java中一切皆为对象,那么,就类似于某些动态语言一样,函数也可以当成是对象啊!代码块也可以当成是对象啊!随着函数式编程的概念越来越深入人心,java中CODE=OBJECT的这一天终于到来了!如果你认为lambda表达式仅仅是为了从语法上简化匿名内部类,那就太小看jdk8的lambda了!

下面我们就来看下lambda表达式是如何亮瞎你的眼的!

lambda的定义
Funda-men-tally, a lambda expression is just a shorter way of writing an implementation of a method for later execution. 
(1)lambda是方法的实现
(2)lambda是延迟执行的

首先看一个用匿名内部类的例子:

public class Test1{
        public static void main(String args[]){
                Runnable r = new Runnable(){
                        public void run(){
                                System.out.println("hello,lambda!");
                        }
                };
                r.run();
        }
}
要换成lambda是什么样的呢?

public class Test2{
        public static void main(String args[]){
                Runnable r = ()->System.out.println("hello,lambda");
                r.run();
        }
}
原先要5行代码,现在换成了仅仅1行!
这他妈的得省多少代码啊!
有木有很兴奋啊!
下面还有更刺激的!

lambda是如何做到的呢?看一下反编译之后的字节码:

public static void main(java.lang.String[]);
    descriptor: ([Ljava/lang/String;)V
    flags: ACC_PUBLIC, ACC_STATIC
    Code:
      stack=1, locals=2, args_size=1
         0: invokedynamic #2,  0              // InvokeDynamic #0:run:()Ljava/lang/Runnable;
         5: astore_1      
         6: aload_1       
         7: invokeinterface #3,  1            // InterfaceMethod java/lang/Runnable.run:()V
        12: return        
      LineNumberTable:
        line 3: 0
        line 4: 6
        line 5: 12
}
注意:上面有一个叫做invokedynamic的指令。invokedynamic是从jdk7开始引入的,jdk8开始落地。
可以看出来lambda并不是语法糖,它不是像匿名内部类那样生成那种带有$的匿名类。
简单的说,这里只是定义了一个方法调用点,具体调用那个方法要到运行时才能决定,这就是前面所说的:延迟执行。
具体的细节请google:invokedynamic。

为了配合lambda,jdk8引入了一个新的定义叫做:函数式接口(Functional interfaces)
函数式接口:
it is an interface that requires exactly one method to be implemented in order to satisfy the requirements of the interface. 
(1)是一个接口
(2)只有一个待实现的方法
因为jdk8开始,接口可以有default方法,所以,函数式接口也是可以有default方法的,但是,只能有一个未实现的方法。

与此对应,新引入了一个注解: @FunctionalInterface
这个注解只是起文档的作用,说明这个接口是函数式接口,编译器并不会使用这个注解来决定一个接口是不是函数式接口。
不管加不加@FunctionalInterface这个注解,下面的接口都是函数式接口:
interface Something {
  public String doit(Integer i);
}

lambda的语法
A lambda in Java essentially consists of three parts: a parenthesized set of parameters, an arrow, and then a body, 
which can either be a single expression or a block of Java code.
lambda包含3个部分:
(1)括弧包起来的参数
(2)一个箭头
(3)方法体,可以是单个语句,也可以是语句块
参数可以写类型,也可以不写,jvm很智能的,它能自己推算出来

public class Test3{
        public static void main(String... args) {
            Comparator c = (String lhs, String rhs) -> lhs.compareTo(rhs);
            int result = c.compare("Hello", "World");
                System.out.println(result);
        }
}
方法可以有返回,也可以无返回,如果有多个语句,还要返回值,需要加上return

public class Test4{
        public static void main(String... args) {
            Comparator c =(lhs, rhs) ->{
                      System.out.println("I am comparing " +lhs + " to " + rhs);
                          return lhs.compareTo(rhs);
                };
                int result = c.compare("Hello", "World");
                System.out.println(result);
        } 
}


一个很有意思的事情:
之前我们说Object是一切类的父类,然而在加入了lambda以后,这种大一统的局面将不复存在:

public class Test5{
        public static void main(String args[]){
                Object r = ()->System.out.println("hello,lambda");
        }

}
编译报错:
Test5.java:3: error: incompatible types: Object is not a functional interface
                Object r = ()->System.out.println("hello,lambda");
                           ^
1 error

很显然,编译器会检查变量的引用类型里面是否真的是一个函数式接口。那么如何让这段代码通过编译呢?
只需要加一个强制类型转换就可以了:

public class Test6{
        public static void main(String args[]){
                Object r = (Runnable)()->System.out.println("hello,lambda");
        }

}
lambda的词法作用域

我们知道,在匿名内部类中:

class Hello {
  public Runnable r = new Runnable() {
      public void run() {
        System.out.println(this);
        System.out.println(toString());
      }
    };

  public String toString() {
    return "Hello's custom toString()";
  }
}

public class InnerClassExamples {
  public static void main(String... args) {
    Hello h = new Hello();
    h.r.run();
  }
} 
System.out.println(this);这里的this指的是匿名类,而非Hello类。
想要引用Hello类需要Hello.this这样:

class Hello {
  public Runnable r = new Runnable() {
      public void run() {
        System.out.println(Hello.this);
        System.out.println(Hello.this.toString());
      }
    };
}
这种做法非常的反人类反直觉!看上去很恶心!
下面我们就来看一下伟大的lambda是什么样子的:

class Hello{
        public Runnable r = () -> {
             System.out.println(this);
             System.out.println(toString());
        };

        public String toString() {
                  return "Hello's custom toString()";
        }
}
public class Test7{
        public static void main(String args[]){
                    Hello h = new Hello();
                    h.r.run();
        }
}
输出:
Hello's custom toString()
Hello's custom toString()
System.out.println(this);这里的this指的是Hello,而非lambda表达式!
但是,如果我们想在lambda表达式中返回lambda本身该怎么做呢?

变量捕获
匿名内部类只能引用作用域外面的final的变量,在lambda中对这个限制做了削弱,只需要是“等价final”就可以,没必要用final关键字来标识。
public class Test8{
        public static void main(String args[]){
                String message = "Howdy, world!";//不需要是final的
                Runnable r = () -> System.out.println(message);//这里也能访问
                r.run();
        }
}
“等效final”的意思是:事实上的final,所以,一旦赋值也是不可以改变的!比如:

public class Test9{
        public static void main(String args[]){
                String message = "Howdy, world!";
                Runnable r = () -> System.out.println(message);
                r.run();
                message = "change it";
        }
}
Test9.java:4: error: local variables referenced from a lambda expression must be final or effectively final
                Runnable r = () -> System.out.println(message);
                                                      ^
1 error

如果上面的内容看上去平淡无奇的话,真正的大杀器出现了:方法引用
我们有一个这样的类:

class Person {
  public String firstName;
  public String lastName;
  public int age;
}
现在我们要把多个Person对象进行排序,有时候是按照firstName来排,有时候是按照lastName或者是age来排,使用lambda可以这样来做:

class Person{
        public String firstName;
        public String lastName;
        public int age;
        public Person(String firstName, String lastName, int age){
                this.firstName = firstName;
                this.lastName = lastName;
                this.age = age;
        }
        public String toString(){
                return firstName+","+lastName+","+age;
        }
}
public class Test10{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 41),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Neward", 19),
                        new Person("Matthew", "Neward", 13)
                };
                //sort by firstName
                Arrays.sort(people, (lhs,rhs)->lhs.firstName.compareTo(rhs.firstName));
                for(Person p : people){
                        System.out.println(p);
                }
        }
}
我们可以把Comparator抽取出来,变成是Person对象的成员变量:

class Person{
        public String firstName;
        public String lastName;
        public int age;
        public Person(String firstName, String lastName, int age){
                this.firstName = firstName;
                this.lastName = lastName;
                this.age = age;
        }
        public String toString(){
                return firstName+","+lastName+","+age;
        }
        public final static Comparator compareFirstName =
            (lhs, rhs) -> lhs.firstName.compareTo(rhs.firstName);

        public final static Comparator compareLastName =
            (lhs, rhs) -> lhs.lastName.compareTo(rhs.lastName);

        public final static Comparator compareAge =
            (lhs, rhs) -> lhs.age - rhs.age;
}
public class Test11{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 41),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Neward", 19),
                        new Person("Matthew", "Neward", 13)
                };
                Arrays.sort(people, Person.compareFirstName);//这里直接引用lambda
                for(Person p : people){
                        System.out.println(p);
                }
        }
}
能起到同样的作用,但是语法看上去很奇怪,因为之前我们都是创建一个满足Comparator签名的方法,然后直接调用,而非定义一个变量,
然后引用这个变量!所以,还有这么一种调用方法:

class Person{
        public String firstName;
        public String lastName;
        public int age;
        public Person(String firstName, String lastName, int age){
                this.firstName = firstName;
                this.lastName = lastName;
                this.age = age;
        }
        public String toString(){
                return firstName+","+lastName+","+age;
        }
        public static int compareFirstName(Person lhs, Person rhs){
                return lhs.firstName.compareTo(rhs.firstName);
        } 
        public static int compareLastName(Person lhs, Person rhs){
             return lhs.lastName.compareTo(rhs.lastName);
        }
}
public class Test12{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 41),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Neward", 19),
                        new Person("Matthew", "Neward", 13)
                };
                Arrays.sort(people, Person::compareFirstName);
                for(Person p : people){
                        System.out.println(p);
                }
        }
}
看Person::compareFirstName这种调用方式,
如果是static方法使用:类名::方法名
如果是instance方法:instance::方法名

但是,上面的代码还是不是很美观,因为Person只是一个数据对象,它不应该的对外提供compareFirstName或者是compareLastName这样的方法,
我们需要的仅仅是根据某个字段排序而已!很幸运的是jdk的api帮我们做了这件事:

import java.util.*;
class Person{
        public String firstName;
        public String lastName;
        public int age;
        public Person(String firstName, String lastName, int age){
                this.firstName = firstName;
                this.lastName = lastName;
                this.age = age;
        }
        public String getFirstName(){
                return this.firstName;
        }
        public String getLastName(){
                return this.lastName;
        }
        public String toString(){
                return firstName+","+lastName+","+age;
        }
}
public class Test13{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 41),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Neward", 19),
                        new Person("Matthew", "Neward", 13)
                };
                Arrays.sort(people, Comparator.comparing(Person::getFirstName));
                for(Person p : people){
                        System.out.println(p);
                }
        }
}
Arrays.sort(people, Comparator.comparing(Person::getFirstName));这里调用了Comparator.comparing方法,
但是注意这里的Person::getFirstName,很显然getFirstName()并不是static的,这是jdk做了封装的缘故!
这样做就非常完美了!

假如我们的排序算法改为:先按照lastName,然后按照age排序呢?

public class Test15{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 10),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Naward", 19),
                        new Person("Matthew", "Nmward", 13)
                };
                Collections.sort(Arrays.asList(people), (lhs, rhs)->{
                        if(lhs.getLastName().equals(rhs.getLastName())){
                                return lhs.getAge()-rhs.getAge();
                        }else{
                                return lhs.getLastName().compareTo(rhs.getLastName());
                        }
                });
                for(Person p : people){
                        System.out.println(p);
                }
        }
}
很显然,应该还有更好的实现方式:

public class Test16{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 10),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Naward", 19),
                        new Person("Matthew", "Nmward", 13)
                };
                Collections.sort(Arrays.asList(people),Comparator.comparing(Person::getLastName).thenComparing(Person::getAge));
                for(Person p : people){
                        System.out.println(p);
                }
        }
}
Comparator.comparing(Person::getLastName).thenComparing(Person::getAge):简直帅呆了!
还有更多的诸如:andThen()这样的方法,可以查api。

虚方法扩展
因为接口可以有default方法,所以很多类库都重写了,加入了一些default的方法,比如:
interface Iterator {
  boolean hasNext();
  T next();
  void remove();
  void skip(int i) default {
    for (; i > 0 && hasNext(); i--) next();
  }

skip(i)就是一个default方法,这样所有的Iterator的子类都具有了一个叫skip的方法!
但是,大家对default方法的争议还是比较大的,比如:

interface I1 {
        public default void print(){
                System.out.println("I1");
        }
        public void hello();
}
interface I2{
        public default void print(){
                System.out.println("I2");
        }
        public void world();
}
class Impl implements I1,I2{
        public void hello(){
        }
        public void world(){
        }
}
如果在Impl上调用print会怎样呢?这不就是传说中的多继承么?想知道结果的话,自己试一下就可以了,哈哈

Stream:
之前的文章已经有介绍,下面只据一些使用的例子:
过滤age>12的元素:

people
      .stream()
      .filter(it -> it.getAge() >= 21) ;
过滤age>12的元素,并输出:

 people.stream()
      .filter((it) -> it.getAge() >= 21)
      .forEach((it) -> 
        System.out.println("Have a beer, " + it.getFirstName())); 
jdk预定义的Predicate:

Predicate drinkingAge = (it) -> it.getAge() >= 21;
Predicate brown = (it) -> it.getLastName().equals("Brown");
people.stream()
      .filter(drinkingAge.and(brown))
      .forEach((it) ->System.out.println("Have a beer, " + it.getFirstName()));
map:

IntStream ages =
      people.stream()
            .mapToInt((it) -> it.getAge()); 
//sum:
int sum = people.stream()
                .mapToInt(Person::getAge)
                .sum(); 
重点说下reduce:

public class Test17{
        public static void main(String args[]){
                List values = Arrays.asList(1,2,3,4,5);
                int sum = values.stream().reduce(0, (l,r)->l+r);
                System.out.println(sum);
        }
}
reduce(0, (l,r)->l+r)的工作原理是:第一个参数0作为后面lambda表达式的左操作数,然后从stream中取出一个元素作为右操作数,
二者运算的结果作为下一次运算的左操作数,依次循环。
最后看一个好玩的例子:

class Person{
        public String firstName;
        public String lastName;
        public int age;
        public Person(String firstName, String lastName, int age){
                this.firstName = firstName;
                this.lastName = lastName;
                this.age = age;
        }
        public String getFirstName(){
                return this.firstName;
        }
        public String getLastName(){
                return this.lastName;
        }
        public int getAge(){
                return this.age;
        }
        public String toString(){
                return firstName+","+lastName+","+age;
        }
        public String toJson(){
                return "{"+
                                "firstName:\""+firstName+"\","+
                                "lastName:\""+lastName+"\","+
                                "age:"+age +
                                "}";
        }
}
public class Test18{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 10),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Naward", 19),
                        new Person("Matthew", "Nmward", 13)
                };
                String json = Arrays.asList(people).stream().map(Person::toJson).reduce("[",(l,r)->l + (l.equals("[")?"":",") + r)+"]";
                System.out.println(json);
        }
}
输出结果:
[{firstName:"Ted",lastName:"Neward",age:10},{firstName:"Charlotte",lastName:"Neward",age:41},{firstName:"Michael",lastName:"Naward",age:19},{firstName:"Matthew",lastName:"Nmward",age:13}]
还可以这样:

public class Test19{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 10),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Naward", 19),
                        new Person("Matthew", "Nmward", 13)
                };
                String joined = Arrays.asList(people).stream().map(Person::toJson).collect(Collectors.joining(", "));
            	System.out.println("[" + joined + "]"); 
        }
}
更进一步:
public class Test20{
        public static void main(String args[]){
                Person people[] = new Person[]{
                        new Person("Ted", "Neward", 10),
                        new Person("Charlotte", "Neward", 41),
                        new Person("Michael", "Naward", 19),
                        new Person("Matthew", "Nmward", 13)
                };
                String json = Arrays.asList(people).stream().map(Person::toJson).collect(Collectors.joining(", ", "[", "]"));
                System.out.println(json);
        }
}
如果只能用一个字来形容,那就是perfect!
参考:
http://www.oracle.com/technetwork/articles/java/architect-lambdas-part1-2080972.html
http://www.oracle.com/technetwork/articles/java/architect-lambdas-part2-2081439.html

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