小程序-利用递归判断数组是否递增

#include "stdafx.h"

void Judge( int *a, int n)
{
    if (n == 1){ printf ( "递增" ); }
    if (n != 1)
    {
        if (a[n-1] >= a[n - 2]){ Judge(a, n - 1); }
        if (a[n-1] < a[n - 2]){ printf ( "非递增" ); }
    }
}
int _tmain( int argc, _TCHAR* argv[])
{
    int a[] = {1,2,3,3,4,5};
    int len = sizeof (a) / sizeof (a[0]);
    Judge(a, len);
    getchar ();
    return 0;
}