hdu1004 let the balloon rise map映射

Let the Balloon Rise

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 139579    Accepted Submission(s): 55180


Problem Description
Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you. 
 

Input
Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.
 

Output
For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
 

Sample Input
 
   
5 green red blue red red 3 pink orange pink 0
 

Sample Output
 
   
red pink
 

Author
#include
#include//string类的变量尽量用C++的cin cout读入输出 
#include 
using namespace std;
//用模拟也能做 数据量不是太大。也可以当map练手题 
int main()
{
	int t,num,max;
	string s,smax;
	
	while(cin>>t&&t)
	{
		max=0;
		mapm;
		while(t--)
		{
			cin>>s;
			m[s]++;
			if(m[s]>max)
			{
				max=m[s];
				smax=s;
			}
		}
		cout<

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