Leetcode 283. Move Zeros

Given an array nums, write a function to move all 0’s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.

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要求很简单，把数组中所有的0元素移到数组最后面去。
我的思路是，两个指针i,j指向头部，指针i遍历，每当遇到不为零的数就赋值给Nums[j]，最后将指针j后面全部赋予0值就行了。

只要将所有合格的元素移动到最前端就行了，后面补0
o(n)

class Solution {
    public void moveZeroes(int[] nums) {
        if (nums == null || nums.length == 0) return; 
        int j = 0;
        for(int i = 0; iif(nums[i] != 0)  nums[j++] = nums[i];
        }

        while(j < nums.length){
            nums[j++] = 0;
        }   
    }
}