python循环套用递归进行多层json解析

废话不多说。。。这个循环递归真是折磨了我两天。。。

上代码解析一个四层json

# -*- coding:utf-8 -*-
'''
Created on 2019

@author: pt0521
'''
import re
import json as js
import sys
def get_json_nums_of_layers(file_path):
    fo=open(file_path,'r',encoding='utf-8')
    jsonstr = fo.read()#将json作为整个的字符串读取进去
    pos1=list()#用于存放
    for m in re.finditer('{', jsonstr):
        pos1.append(m.start())
    print(pos1)
    pos2=jsonstr.find('}')
    print(pos2)
    for i in range(len(pos1)):
        if pos1[i]>pos2:
            return i
        else:
            return len(pos1)
    fo.close()
 
def get_json(file_path,nums_layer_toget):
    obj={}
    num=1
    if(nums_layer_toget>get_json_nums_of_layers(file_path)):
        print("所要解析的层数超过该json拥有的层数！请修正")
    else:
        fo=open(file_path,'r',encoding='utf-8')
        jsonstr = fo.read()
        jsonstr=js.loads(jsonstr)
        get_json_operation(jsonstr, nums_layer_toget,obj)
                        
def get_json_operation(jsonstr,nums_layer_toget,obj):
    while(nums_layer_toget>=0):
        if nums_layer_toget==0:
            return nums_layer_toget+1
        else:
            m=list(jsonstr.keys())
            print('这一层的键有',m)
            for key in jsonstr:
#                 print(key)
                if isinstance(jsonstr[key], list) and nums_layer_toget>=1:
                    print('该层列表有',len(jsonstr[key]),'个元素') 
                    j=0
                    cd=len(jsonstr[key])
                    temp_json=jsonstr[key]
                    if j<=cd-1:                 
                        jsonstr=jsonstr[key][j]
#                         print(jsonstr)
                        get_json_operation(jsonstr, nums_layer_toget-1,obj)
                        j=j+1
                        if j==cd:                     
                            return nums_layer_toget+1 
                        else:
                            while(j