http://www.elijahqi.win/archives/3560
Petr likes to come up with problems about randomly generated data. This time problem is about random permutation. He decided to generate a random permutation this way: he takes identity permutation of numbers from 1
1
to n
n
and then 3n
3n
times takes a random pair of different elements and swaps them. Alex envies Petr and tries to imitate him in all kind of things. Alex has also come up with a problem about random permutation. He generates a random permutation just like Petr but swaps elements 7n+1
7n+1
times instead of 3n
3n
times. Because it is more random, OK?!
You somehow get a test from one of these problems and now you want to know from which one.
Input
In the first line of input there is one integer n
n
(103≤n≤106
103≤n≤106
).
In the second line there are n
n
distinct integers between 1
1
and n
n
— the permutation of size n
n
from the test.
It is guaranteed that all tests except for sample are generated this way: First we choose n
n
— the size of the permutation. Then we randomly choose a method to generate a permutation — the one of Petr or the one of Alex. Then we generate a permutation using chosen method.
Output
If the test is generated via Petr’s method print “Petr” (without quotes). If the test is generated via Alex’s method print “Um_nik” (without quotes).
Example
input
Copy
5
2 4 5 1 3
output
Copy
Petr
Note
Please note that the sample is not a valid test (because of limitations for n
n
) and is given only to illustrate input/output format. Your program still has to print correct answer to this test to get AC.
Due to randomness of input hacks in this problem are forbidden.
大爷题解
https://blog.csdn.net/icefox_zhx/article/details/80520051
#include
#include
#include
#define ll long long
using namespace std;
inline char gc(){
static char now[1<<16],*S,*T;
if (T==S){T=(S=now)+fread(now,1,1<<16,stdin);if (T==S) return EOF;}
return *S++;
}
inline int read(){
int x=0,f=1;char ch=gc();
while(!isdigit(ch)) {if (ch=='-') f=-1;ch=gc();}
while(isdigit(ch)) x=x*10+ch-'0',ch=gc();
return x*f;
}
const int N=1e6+10;
int s[N],n,a[N];ll ans;
inline void add(int x,int v){
while(x<=n) s[x]+=v,x+=x&-x;
}
inline int query(int x){
ll tmp=0;
while(x) tmp+=s[x],x-=x&-x;return tmp;
}
int main(){
// freopen("e.in","r",stdin);
n=read();
for (int i=1;i<=n;++i) a[i]=read();
for (int i=n;i;--i){
ans+=query(a[i]);
add(a[i],1);
}
ans&=1;n&=1;
if (ans==n) puts("Petr");
else puts("Um_nik");
return 0;
}