HihoCoder1683模拟

题目链接:http://hihocoder.com/problemset

题解:枚举行数,然后随便模拟下。

#include 

using namespace std;
const int N = 10007;
using ll = long long ;
using ld = long double ;
#define ALL(X) begin(X), end(X)
#define mp make_pair
#define SZ(X) ((int)X.size())
string T;
int n, K;
int line[N], ans[N];
int bit(int num)
{
    int cnt = 0;
    if(!num) return 1;
    while(num) cnt ++, num /= 10;  return cnt;
}
bool check(int h)
{
    for(int i = 1;i <= h;i ++) ans[i]=0;
    int p = 0, cnt = 1, now = 0;
    for(int i = 1;i <= h;i ++) line[i] = K - (bit(i) + bit(h) + 3);
    while(p < n) {
        if(cnt > h) return 0;
        if(T[p] == ' ') {
            ans[cnt] ++;
            p ++;
            now ++;
            if(now >= line[cnt]) {
                cnt ++;
                now = 0;
            }
        } else {
            int tmp = p, tnow = now;
            while(tmp < n && T[tmp] != ' ') {
                now ++;
                tmp ++;
            }
            if(now <= line[cnt]) {
                while(p < tmp) {
                    ans[cnt] ++;
                    p ++;
                }
                if(now == line[cnt]) {
                    cnt ++;
                    now = 0;
                }
            } else {
                cnt ++;
                now = 0;
            }
        }
    }
    return cnt <= h;
}
int main()
{
    cin >> K;
    char ch = getchar();
    while(ch != '\n') ch = getchar();
    getline(cin, T);
    n = SZ(T);
    int i;
    for(i = 1;i <= n;i ++) {
        if(check(i)) break;
    }
    int st = 0;
    for(int j = 1;j <= i;j ++) {
        for(int k = 1;k <= ans[j];k ++) {
            cout << T[st++];
        }
        printf("(%d/%d)\n",j,i);
    }
    return 0;
}


你可能感兴趣的:(弱鸡的日常,思维题,模拟)