摄影测量光束法区域网平差编程实现

最近做课程设计需要用到光束法区域网平差的知识，我用C++编程语言来实现了整个光束法区域网平差过程的实现，本代码是基于我前面发布的摄影测量内定向编程实现、摄影测量前方交会编程实现来说的，代码中有些地方看不懂的小伙伴，可以看看我以上两篇文章叙述的内容，下面是我的代码：

//光束法区域网平差
#include
#include
#include 
//#include "core/core.hpp"
#define _CRT_SECURE_NO_WARNINGS

using namespace std;
//using namespace cv;

int main()
{
	//定义内方位元素
	double x0 = -0.00000;//mm
	double y0 = 0.00000;//mm
	double f = 0.0705;//mm
	//从文件中读取相应的数值到数组
	double array[12] = { 0.0 };
	ifstream infile;//定义文件流对象
	infile.open("C:\\Users\\ASUS\\Desktop\\7\\2036\\8.txt");//打开文档C:\Users\ASUS\Desktop\7\1036
	double *ptr = &array[0];
	while (!infile.eof())
	{
		infile >> *ptr;//这是把文档里面的数对应放在ptr位置上的数值上
		ptr++;
	}
	infile.close();
	double n = array[0];
	double x = array[1];
	double y = array[2];
	double X = array[3];
	double Y = array[4];
	double Z = array[5];
	double Xs = array[6];
	double Ys = array[7];
	double Zs = array[8];
	double phi = array[9];
	double omiga = array[10];
	double kappa = array[11];
	/*double flag = array[12];*/
	//计算phi、omiga、kappa的方向余弦
	double a1 = cos(phi)*cos(kappa) - sin(phi)*sin(omiga)*sin(kappa);
	double a2 = -cos(phi)*sin(kappa) - sin(phi)*sin(omiga)*cos(kappa);
	double a3 = -sin(phi)*cos(omiga);
	double b1 = cos(omiga)*sin(kappa);
	double b2 = cos(omiga)*cos(kappa);
	double b3 = -sin(omiga);
	double c1 = sin(phi)*cos(kappa) + cos(phi)*sin(omiga)*sin(kappa);
	double c2 = -sin(phi)*sin(kappa) + cos(phi)*sin(omiga)*cos(kappa);
	double c3 = cos(phi)*cos(omiga);
	//利用共线条件方程就求解Lx、Ly,构建矩阵L
	double x1 = (-f * (a1*(X - Xs) + b1 * (Y - Ys) + c1 * (Z - Zs)))/(a3*(X - Xs) + b3 * (Y - Ys) + c3 * (Z - Zs));
	double y1=(-f * (a2*(X - Xs) + b2 * (Y - Ys) + c2 * (Z - Zs))) / (a3*(X - Xs) + b3 * (Y - Ys) + c3 * (Z - Zs));
	double Lx = x - x1;
	double Ly = y - y1;

//构建A、B矩阵
//建立矩阵A、B,使用严密解形式
double a11 = (a1 * f + a3 * x)*(1.0/Z);
double a12 = (b1 * f + b3 * x)*(1.0 / Z);
double a13 = (c1 * f + c3 * x)*(1.0 / Z);
//老师提供的严密解形式
double a14 = y * sin(omiga) - ((x*(x*cos(kappa) - y * sin(kappa)) / f + f * cos(kappa)))*cos(omiga);
double a15 = -f * sin(kappa) - (x*(x*sin(kappa)+y*cos(kappa))) / f;
//课本上严密解形式
/*double a14 = (b1*x*y) / f - b2 * (f + (x*x) / f) - b3 * y;
double a15 = -(sin(kappa)*x*x) / f - (x*y*sin(kappa)) / f - f * sin(kappa);*/
double a16 = y;
double a21 = (a2 * f + a3 * y)*(1.0 / Z);
double a22 = (b2 * f + b3 * y)*(1.0 / Z);
double a23 =(c2 * f + c3 * y)*(1.0 / Z);
double a24 = -x * sin(omiga) - cos(omiga)*((x*(x*cos(kappa) - y * sin(kappa))) / f - f * sin(kappa));
double a25 = -f*cos(kappa)-(y*(x*sin(kappa)+y*cos(kappa)))/f;
/*double a24 = b1 * (f + (y*y) / f) - (b2*x*y) / f + b3 * x;
double a25 = -(x*y*sin(kappa)) / f - (y*y*cos(kappa)) / f - f * cos(kappa);*/
double a26 = -x;
double A[2][6] = {0.0};

A[0][0] = a11;
A[0][1] = a12;
A[0][2] = a13;
A[0][3] = a14;
A[0][4] = a15;
A[0][5] = a16;
A[1][0] = a21;
A[1][1] = a22;
A[1][2] = a23;
A[1][3] = a24;
A[1][4] = a25;
A[1][5] = a26;
ofstream fout("C:\\Users\\ASUS\\Desktop\\7\\2036\\8_result.txt", ios_base::app);
int i, j;
fout <<"像片号："<< n << endl;
fout << "A=" << endl;
for (i = 0; i < 2; i++)
{
	for (j = 0; j < 6; j++)
		
		fout << A[i][j] << " ";
	if (j % 6 == 0)
		fout << endl;
}
fout << "B=" << endl;
for (int m = 0; m < 2; m++)
{
	for (n = 0; n < 3; n++)
	
	fout << -A[m][(int )n] << " ";
	if ((int)n % 3 == 0)
		fout << endl;
}
fout << "L=" << endl;
fout<< Lx*1000 << endl;
fout << Ly * 1000 << endl;
//cout << Lx << "  " << Ly << endl;
/*cout.precision(12);
cout << Lx << endl;
cout << Ly << endl;*/
/*Mat L = Mat::zeros(2, 1, CV_64F);
L.at(0, 0) = Lx;
L.at(1, 0) = Ly;*/
/*Mat A = Mat::zeros(2, 6, CV_64F);
A.at(0, 0) = a11;
A.at(0, 1) = a12;
A.at(0, 2) = a13;
A.at(0, 3) = a14;
A.at(0, 4) = a15;
A.at(0, 5) = a16;
A.at(1, 0) = a21;
A.at(1, 1) = a22;
A.at(1, 2) = a23;
A.at(1, 3) = a24;
A.at(1, 4) = a25;
A.at(1, 5) = a26;*/
/*Mat B = Mat::zeros(2, 3, CV_64F);
B.at(0, 0) = -a11;
B.at(0, 1) = -a12;
B.at(0, 2) = -a13;
B.at(1, 0) = -a21;
B.at(1, 1) = -a22;
B.at(1, 2) = -a23;*/
/*cout.precision(3);*/
/*cout << A << endl;*/
//cout << B << endl;
/*fout << "L=" << endl;
fout << L << endl;*/
//int i, j;
//for ( i = 0; i< 2;i++)
//{
//	for(j=0;j<6;j++)
//	  fout.precision(12);//控制输出的位数
//	fout << A.at(i, j)<< "  ";
//		if (j % 6 == 0)
//			fout << '\n';
//}
/*fout << n << endl;
fout << "A=" << endl;
fout << A << endl;
fout << "B=" << endl;
fout << B << endl;
fout << "L=" << endl;
fout << L << endl;*/
/*fout << a11 << endl;*/
cout << "You have finished the work, congrtulations!!!!" << endl;
system("pause");
return 0;

}