将ResultSet转为List

2019独角兽企业重金招聘Python工程师标准>>>

public static List resultSetToList(ResultSet rs) throws java.sql.SQLException {   
           if (rs == null)   
               return Collections.EMPTY_LIST;   
           ResultSetMetaData md = rs.getMetaData(); //得到结果集(rs)的结构信息，比如字段数、字段名等   
           int columnCount = md.getColumnCount(); //返回此 ResultSet 对象中的列数   
           List list = new ArrayList();   
           Map rowData = new HashMap();   
           while (rs.next()) {   
            rowData = new HashMap(columnCount);   
            for (int i = 1; i <= columnCount; i++) {   
                    rowData.put(md.getColumnName(i), rs.getObject(i));   
            }   
            list.add(rowData);   
            System.out.println("list:" + list.toString());   
           }   
           return list;   
   }

接着在其他方法里处理返回的List

List ls = resultSetToList(rs);   
Iterator it = ls.iterator();   
while(it.hasNext()) {   
    Map hm = (Map)it.next();   
    System.out.println(hm.get("字段名大写"));   
}

 

转载于:https://my.oschina.net/xinyuanKong/blog/674587