C#参数传递的方式

C#中与参数有关系的关键字有三个params、ref及out
params

The params keyword lets you specify a method parameter that takes an argument where the number of arguments is variable.No additional parameters are permitted after the params keyword in a method declaration, and only one params keyword is permitted in a method declaration.

 

params
    public static void UseParams(params int[] list)// params修饰的参数必须是一维数组
    {
        for (int i = 0; i < list.Length; i++)
            Console.WriteLine(list[i]);
        Console.WriteLine();
    }

    public static void UseParams2(params object[] list)// params修饰的参数必须是一维数组
    {
        for (int i = 0; i < list.Length; i++)
            Console.WriteLine(list[i]);
        Console.WriteLine();
    }

    public static void Main()
    {
        UseParams(1, 2, 3);
        UseParams2(1, 'a', "test");

        int[] myarray = new int[3] { 10, 11, 12 };// 这种方式要先构造好一个数组，显然要更麻烦一些
        UseParams(myarray);
    }

输出结果是
1
2
3

1
a
test

10
11
12
ref
The ref keyword causes arguments to be passed by reference. The effect is that any changes to the parameter in the method will be reflected in that variable when control passes back to the calling method.

• An argument passed to a ref parameter must first be initialized. This differs from out, whose arguments do not have to be explicitly initialized before they are passed.
• Although the ref and out keywords cause different run-time behavior, they are not considered part of the method signature at compile time. Therefore, methods cannot be overloaded if the only difference is that one method takes a ref argument and the other takes an out argument.
• however, if one method takes a ref or out argument and the other uses neither,it is OK. 

• Properties are not variables. They are actually methods, and therefore cannot be passed as ref parameters. 

看下面的例子：

Code
class CS0663_Example 
{
    // compiler error CS0663: "cannot define overloaded 
    // methods that differ only on ref and out"
    public void SampleMethod(ref int i) {  }
    public void SampleMethod(out int i) {  }
}

Do not confuse the concept of passing by reference with the concept of reference types. The two concepts are not related; a method parameter can be modified by ref regardless of whether it is a value type or a reference type. Therefore, there is no boxing of a value type when it is passed by reference. To use a ref parameter, both the method definition and the calling method must explicitly use the ref keyword.

reference(引用)的概念来源于C++

out
out与ref的不同之处在于：

• variables passed as out arguments do not have to be initialized before being passed
• the called method is required to assign a value before the method returns.

使用ref和out传递数组
与所有的 out 参数一样，在使用数组类型的 out 参数前必须先为其赋值，即必须由被调用方为其赋值。例如：

static   void  TestMethod1( out   int [] arr)
{
    arr  =   new   int [ 10 ];    //  definite assignment of arr
}

与所有的 ref 参数一样，数组类型的 ref 参数必须由调用方明确赋值。因此不需要由接受方明确赋值。可以将数组类型的 ref 参数更改为调用的结果。例如，可以为数组赋以 null 值，或将其初始化为另一个数组。例如：

static   void  TestMethod2( ref   int [] arr)
{
    arr  =   new   int [ 10 ];    //  arr initialized to a different array
}

传递数组时，ref和out的使用并没有特殊之处。