如何计算自己哪天打扫卫生

办公室总共12个人，分为6个小组，每天要有一组人打扫卫生。
我们的工作日是：周一到周五
给一个初始日期，算出本年度，这个小组值日日期！

-- 构造数据
select   identity ( int , 1 , 1 )  as  iid, *  
into  # temp
from  
(
select   top   100   percent   [ date ] = dateadd ( day ,id, ' 2004-01-01 ' ), [ weekday ] = datename (weekday, dateadd ( day ,id, ' 2004-01-01 ' ))
  from  (
select  id = a.id + b.id * 10 + c.id * 100   from  
(
     select  id = 0   union   all   select   1
     union   all   select  id = 2   union   all   select   3
     union   all   select  id = 4   union   all   select   5
     union   all   select  id = 6   union   all   select   7
     union   all   select  id = 8   union   all   select   9
) a,(
     select  id = 0   union   all   select   1
     union   all   select  id = 2   union   all   select   3
     union   all   select  id = 4   union   all   select   5
     union   all   select  id = 6   union   all   select   7
     union   all   select  id = 8   union   all   select   9
) b,(
     select  id = 0   union   all   select   1
     union   all   select  id = 2   union   all   select   3
) c
) aa
where   datepart (weekday, dateadd ( day ,id, ' 2004-01-01 ' ))  between   2   and   6
and   id  between   0   and   366
order   by  id
) bb

-- 查询
select   [ date ] = convert ( varchar ( 10 ), [ date ] , 120 ), [ weekday ]   from  # temp
where  iid % 6   =  ( select  iid  from  # temp   where   [ date ]   =   ' 2004-11-16 ' ) % 6  

-- 删除临时表
drop   table  # temp

问题主要在这里：
where iid%6 = (select iid from #temp where [date] = '2004-11-16')%6
iid为插的序列号, iid被6除的余数只要等于特殊日期(2004-11-16，这天是我值日)被6除的余数相等即可。