python绘制汉诺塔

本文实例为大家分享了python绘制汉诺塔的具体代码，供大家参考，具体内容如下

源码：

import turtle
class Stack:
  def __init__(self):
    self.items = []
  def isEmpty(self):
    return len(self.items) == 0
  def push(self, item):
    self.items.append(item)
  def pop(self):
    return self.items.pop()
  def peek(self):
    if not self.isEmpty():
      return self.items[len(self.items) - 1]
  def size(self):
    return len(self.items)
def drawpole_3(): # 画出汉诺塔的poles
  t = turtle.Turtle()
  t.hideturtle()
  def drawpole_1(k):
    t.up()
    t.pensize(10)
    t.speed(100)
    t.goto(400 * (k - 1), 100)
    t.down()
    t.goto(400 * (k - 1), -100)
    t.goto(400 * (k - 1) - 20, -100)
    t.goto(400 * (k - 1) + 20, -100)
  drawpole_1(0) # 画出汉诺塔的poles[0]
  drawpole_1(1) # 画出汉诺塔的poles[1]
  drawpole_1(2) # 画出汉诺塔的poles[2]
def creat_plates(n): # 制造n个盘子
  plates = [turtle.Turtle() for i in range(n)]
  for i in range(n):
    plates[i].up()
    plates[i].hideturtle()
    plates[i].shape("square")
    plates[i].shapesize(1, 8 - i)
    plates[i].goto(-400, -90 + 20 * i)
    plates[i].showturtle()
  return plates
def pole_stack(): # 制造poles的栈
  poles = [Stack() for i in range(3)]
  return poles
def moveDisk(plates, poles, fp, tp): # 把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp]
  mov = poles[fp].peek()
  plates[mov].goto((fp - 1) * 400, 150)
  plates[mov].goto((tp - 1) * 400, 150)
  l = poles[tp].size() # 确定移动到底部的高度（恰好放在原来最上面的盘子上面）
  plates[mov].goto((tp - 1) * 400, -90 + 20 * l)
def moveTower(plates, poles, height, fromPole, toPole, withPole): # 递归放盘子
  if height >= 1:
    moveTower(plates, poles, height - 1, fromPole, withPole, toPole)
    moveDisk(plates, poles, fromPole, toPole)
    poles[toPole].push(poles[fromPole].pop())
    moveTower(plates, poles, height - 1, withPole, toPole, fromPole)
myscreen = turtle.Screen()
drawpole_3()
n = int(input("请输入汉诺塔的层数并回车:\n"))
plates = creat_plates(n)
poles = pole_stack()
for i in range(n):
  poles[0].push(i)
moveTower(plates, poles, n, 0, 2, 1)
myscreen.exitonclick()

效果图：

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。