C#应用程序随机启动

如果想你写的程序随系统开机一起启动的话，那么你可以照下面这个方法来做。 
RunWhenStart(false, Application.ProductName, Application.StartupPath + @\"\\MUS.exe\"); 
  

        /// <summary> 

        /// 开机启动项 

      /// </summary> 

        /// <param name=\"Started\">是否启动</param> 

        /// <param name=\"name\">启动值的名称</param> 

        /// <param name=\"path\">启动程序的路径</param> 

        public static void RunWhenStart(bool bStarted, string name, string path)

        {

            RegistryKey hklm = Registry.LocalMachine;

            RegistryKey run = hklm.CreateSubKey(@"SOFTWARE\Microsoft\Windows\CurrentVersion\Run\");

            try

            {

                if (bStarted)

                {

                    run.SetValue(name, path);

                }

                else

                {

                    run.DeleteValue(name);

                }

            }

            catch (Exception err)

            {

                MessageBox.Show(err.Message.ToString(), "系统提示", MessageBoxButtons.OK, MessageBoxIcon.Error);

            }

            finally

            {

                hklm.Close();

                run.Close();

            }

        }

添加一个checkbox在启动时显示于用户界面，并添加CheckedChanged事件，即可以通过checkbox设置是否随时启动。
       

         /// <summary>

        /// 设置开机自动启动

      /// </summary>

        /// <param name="sender"></param>

        /// <param name="e"></param>

        private void chrb_CheckedChanged(object sender, EventArgs e)

        {

            string startPath = Application.ExecutablePath;



            RunWhenStart(chrb.Checked, "SendMessage", startPath);

        }