树形结构的Table中获取某一节点的所有叶子节点字符串

递归算法，将叶子节点存入一个空的stringbuilder变量

 1 private void GetLeafIDSb(StringBuilder result, DataTable dt, string childColumnName, string parentColumnName, int Id)

 2         {

 3             DataRow[] temp1 = dt.Select(parentColumnName + "= " + Id + " ");

 4             if (temp1.Length == 0)

 5             {

 6                 result.Append(Id + ",");

 7             }

 8             else

 9             {

10                 foreach (DataRow item2 in temp1)

11                 {

12                     DataRow[] temp2 = dt.Select(parentColumnName + "=" + item2[childColumnName].ToString() + " ");

13                     GetLeafIDSb(result, dt, childColumnName, parentColumnName, int.Parse(item2[childColumnName].ToString()));

14                 }

15             }

16         }

将上方的方法进行包装，返回叶子节点的字符串

1 private string GetLeafIdStr(DataTable dt, string childColumnName, string parentColumnName, int Id)

2         {

3             StringBuilder sb = new StringBuilder();

4             GetLeafIDSb(sb, dt, childColumnName, parentColumnName, Id);

5             sb = sb.Remove(sb.Length - 1, 1);

6             return sb.ToString();

7         }

使用时直接调用下面这个方法即可，会返回指定节点的叶子节点字符串