删除表中重复记录,只保留一行

  1. 我用的SQL语句:
  2. delete from fp_sgfpxx    
    where fphm in (select fphm from fp_sgfpxx group by fphm   having count(fphm) > 1)   
    and rowid not in (select min(rowid) from fp_sgfpxx group by fphm having count(fphm )>1)
  3. 删除重复的发票号码
  4. 查询同一表内多字段同时重复记录的SQL语句   
  5. 来自:7th string   
  6.   
  7.   
  8. 比如现在有一人员表   (表名:peosons)   
  9. 若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来 select    p1.*    from    persons    p1,persons    p2    where    p1.id<>p2.id    and    p1.cardid    =    p2.cardid    and    p1.pname    =    p2.pname    and    p1.address    =    p2.address   
  10. 可以实现上述效果.   
  11. 几个删除重复记录的SQL语句   
  12.       
  13. 1.用rowid方法   
  14. 2.用group by方法   
  15. 3.用distinct方法   
  16.       
  17. 1。用rowid方法   
  18. 据据Oracle带的rowid属性,进行判断,是否存在重复,语句如下:   
  19. 查数据:   
  20.       select * from table1 a where rowid !=(select    max(rowid)      
  21.       from table1 b where a.name1=b.name1 and a.name2=b.name2......)   
  22. 删数据:   
  23.      delete    from table1 a where rowid !=(select    max(rowid)      
  24.       from table1 b where a.name1=b.name1 and a.name2=b.name2......)   
  25. 2.group by方法   
  26. 查数据:   
  27.   select count(num), max(name) from student --列出重复的记录数,并列出他的name属性   
  28.   group by num   
  29.   having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次   
  30. 删数据:   
  31.   delete from student   
  32.   group by num   
  33.   having count(num) >1   
  34.   这样的话就把所有重复的都删除了。   
  35. 3.用distinct方法 -对于小的表比较有用   
  36. create table table_new as    select distinct *    from table1 minux   
  37. truncate table table1;   
  38. insert into table1 select * from table_new;   
  39.   
  40.   
  41. 查询及删除重复记录的方法大全   
  42.   
  43. 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断   
  44. select * from people   
  45. where peopleId in (select   peopleId   from   people   group   by   peopleId   having   count(peopleId) > 1)   
  46.   
  47.   
  48. 2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录   
  49. delete from people   
  50. where peopleId   in (select   peopleId   from people   group   by   peopleId    having   count(peopleId) > 1)   
  51. and rowid not in (select min(rowid) from   people   group by peopleId   having count(peopleId )>1)   
  52.   
  53.   
  54. 3、查找表中多余的重复记录(多个字段)   
  55. select * from vitae a   
  56. where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq   having count(*) > 1)   
  57.   
  58.   
  59. 4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录   
  60. delete from vitae a   
  61. where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)   
  62. and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)   
  63.   
  64.   
  65. 5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录   
  66. select * from vitae a   
  67. where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)   
  68. and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)   
  69.   
  70.   
  71. (二)   
  72. 比方说   
  73. 在A表中存在一个字段“name”,   
  74. 而且不同记录之间的“name”值有可能会相同,   
  75. 现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;   
  76. Select Name,Count(*) From A Group By Name Having Count(*) > 1   
  77. 如果还查性别也相同大则如下:   
  78. Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1   
  79.   
  80.   
  81. (三)   
  82. 方法一   
  83. declare @max integer,@id integer   
  84. declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1   
  85. open cur_rows   
  86. fetch cur_rows into @id,@max   
  87. while @@fetch_status=0   
  88. begin   
  89. select @max = @max -1   
  90. set rowcount @max   
  91. delete from 表名 where 主字段 = @id   
  92. fetch cur_rows into @id,@max   
  93. end   
  94. close cur_rows   
  95. set rowcount 0   
  96.   
  97.   
  98. 方法二   
  99. "重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。   
  100.   
  101.   
  102.   1、对于第一种重复,比较容易解决,使用   
  103. select distinct * from tableName   
  104.   就可以得到无重复记录的结果集。   
  105.   如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除   
  106. select distinct * into #Tmp from tableName   
  107. drop table tableName   
  108. select * into tableName from #Tmp   
  109. drop table #Tmp   
  110.   发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。   
  111.   
  112.   
  113.   2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下   
  114.   假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集   
  115. select identity(int,1,1) as autoID, * into #Tmp from tableName   
  116. select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID   
  117. select * from #Tmp where autoID in(select autoID from #tmp2)   
  118.   最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)   
  119.   
  120.   
  121. (四)   
  122. 查询重复   
  123. select * from tablename where id in (   
  124. select id from tablename   
  125. group by id   
  126. having count(id) > 1   
  127. )
  128. ===========================
  129. 在几千条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复的呢?谢谢!
    1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
    select * from people
    where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

    2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
    delete from people
    where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
    and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

    3、查找表中多余的重复记录(多个字段)
    select * from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

    4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
    delete from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

    5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
    select * from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

    比方说在A表中存在一个字段“name”,而且不同记录之间的“name”值有可能会相同,
    现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
    Select Name,Count(*) From A Group By Name Having Count(*) > 1

    如果还查性别也相同大则如下:
    Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

    2.group by方法

    查数据:
      select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
      group by num
      having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次
    删数据:
      delete from student
      group by num
      having count(num) >1
      这样的话就把所有重复的都删除了。

    3.用distinct方法 -对于小的表比较有用

    create table table_new as select distinct * from table1 minux
    truncate table table1;
    insert into table1 select * from table_new;


    delete select a.* from FLRK1 a inner join FLRK1 b on a.记录号=b.记录号 and
    (a.[ID]=b.[ID] and a.入库日期=b.入库日期 and a.操作时间=b.操作时间)

    delete from FLRK1 where 记录号 in
    (select min(记录号) from FLRK1 group by 记录号 having count(记录号)>1)


    A表结构:

    ID RQ SJ C
    --------------------------------------------
    1 2005-07-14 14:20:50 A1
    2 2005-02-15 05:12:23 A1
    3 2005-07-14 14:20:50 A1
    4 2005-06-16 16:16:16 A2
    5 2005-06-16 16:16:16 A2
    6 2005-05-18 05:10:35 A3
    7 2005-02-15 05:12:23 A1

    --------------------------------------------

    求SQL语句一条,把表A中 RQ,SJ,C 三个字段有相同的重复记录删除.

    得到的结果:

    ID RQ SJ C
    --------------------------------------------
    1 2005-07-14 14:20:50 A1
    2 2005-02-15 05:12:23 A1
    4 2005-06-16 16:16:16 A2
    6 2005-05-18 05:10:35 A3
    --------------------------------------------

    Delete from A Where ID Not In (Select Min(ID) from A Group By RQ,SJ,C )

    Delete a from tb a inner join tb as b on a.fid <b.fid and a.c=b.c and a.rq=b.rq and a.sj=b.sj

    delete from A t
    where exists(select 1 from A where ID <A.ID and SJ=t.SJ and RQ=t.RQ and C=t.c)


    方法一

    declare @max integer,@id integer
    declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) > 1
    open cur_rows
    fetch cur_rows into @id,@max
    while fetch_status=0
    begin
    select @max = @max -1
    set rowcount @max
    delete from 表名 where 主字段 = @id
    fetch cur_rows into @id,@max
    end
    close cur_rows
    set rowcount 0

      方法二

      有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

      1、对于第一种重复,比较容易解决,使用

    select distinct * from tableName


      就可以得到无重复记录的结果集。
      如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除

    select distinct * into #Tmp from tableName
    drop table tableName
    select * into tableName from #Tmp
    drop table #Tmp

      发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

      2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下

      假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

    select identity(int,1,1) as autoID, * into #Tmp from tableName
    select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
    select * from #Tmp where autoID in(select autoID from #tmp2)

      最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

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