35java游戏_Java 7.35 游戏：猜字游戏（C++&Java）

Ps：

有人可能好奇我为什么大费周章的去写主函数，而不直接把所有操作放在类中，Why？类就好比骨干(存放核心的数据和功能)，最好提供接口， 避免了类中的输入输出，当然，这也不是绝对的。

C++：

#include

#include

#include

using namespace std;

class GuessNumber {

public:

void Get();

int Guess(char);

string get_g_word() {

return g_word;

}

string get_word() {

return word;

}

int get_miss() {

return miss;

}

private:

int miss = 0;

string words[7] = { "write","that","important","transform","judge","index","run" };

string word;

string g_word;

};

void GuessNumber::Get() {

srand((unsigned int)time(0)); //随机数

word = words[rand() % 7 ]; //伪随机数？——跟运行时间有关

g_word=string(word.length(), '*');

}

int GuessNumber::Guess(char ch) {

if (word.find(ch) == string::npos) { //字母没有出现在单词中

miss++;

return 2;

}

if (g_word.find(ch) != string::npos) { //已猜过(出现在g_word中)

miss++;

return 1;

}

for (int i = 0; i < word.length(); i++) //猜中，修改g_word

if (word[i] == ch)

g_word[i] = ch;

return 0;

}

int main() {

char ch;

string str;

GuessNumber My;

int key;

while (1) {

My.Get();

while (My.get_g_word() != My.get_word()) {

cout << "(Guess) Enter a letter in word " << My.get_g_word() << " > ";

cin >> ch;

key = My.Guess(ch);

if (key == 2)

cout << " " << ch << " is not in the word" << endl;

else if (key == 1)

cout << " " << ch << " is already in the word" << endl;

}

cout << "The word is " << My.get_word() << ". You missed " << My.get_miss() << " time " << endl;

cout << "Do you want to guess another word? Enter y or n >";

cin >> str;

if (str == "n")

break;

system("cls"); //清屏

}

return 0;

}

Java：

请自己写。