数学趣题——数字翻译器

问题：输入一个正整数N，输出英文表达。例如：1对应one

源码：

   1: #include <stdio.h>

   2:  

   3: char data_1[19][11] = {"one", "two", "three", "four",

   4:                        "five", "six", "seven", "eight",

   5:                        "nine", "ten", "eleven", "twelve",

   6:                        "thirteen", "forteen", "fifteen", "sixteen",

   7:                        "seventeen", "eighteen", "ninteen"

   8:                       };

   9:  

  10: char data_2[8][8] = {"twenty", "thirty", "forty", "fifty",

  11:                      "sixty", "seventy", "eighty", "ninty"

  12:                     };

  13:  

  14: void translation_A(long N);

  15: void translation_B(long a);

  16: void translation_C(long b);

  17:  

  18: void translation_A(long N)

  19: {   /*翻译千位数*/

  20:     long a;

  21:  

  22:     if(N == 0) {

  23:         printf("Zero\n");

  24:         return;

  25:     }

  26:  

  27:     a = N / 1000;

  28:  

  29:     if(a != 0) {

  30:         translation_B(a);

  31:         printf("thousand ");

  32:     }

  33:  

  34:     a = N % 1000;

  35:  

  36:     if(a != 0)

  37:         translation_B(a);

  38: }

  39:  

  40: void translation_B(long a)

  41: {   /*翻译百位数*/

  42:     long b;

  43:     b = a / 100;

  44:  

  45:     if(b != 0) {

  46:         translation_C(b);

  47:         printf("hundred ");

  48:     }

  49:  

  50:     b = a % 100;

  51:  

  52:     if(b != 0)

  53:         translation_C(b);

  54: }

  55:  

  56: void translation_C(long b)

  57: {   /*翻译十位数和个位数*/

  58:     long c;

  59:  

  60:     if(b <= 19)

  61:         printf("%s ", data_1[b-1]);

  62:     else

  63:     {

  64:         c = b / 10;

  65:         printf("%s ", data_2[c-2]);

  66:         c = b % 10;

  67:  

  68:         if(c != 0)

  69:             printf("%s ", data_1[c-1]);

  70:     }

  71: }

  72:  

  73: int main()

  74: {

  75:     long N;

  76:     printf("Please input a longeger from 0~999999\n");

  77:     scanf("%ld", &N);

  78:     translation_A(N);

  79:     return 0;

  80: }