android智慧停车场代码,计算机视觉实战(十三）停车场车位识别(附完整代码)
要做以下几件事情：
一共有多少辆车。
有多少个空余的车位。
哪个停车位被占用了，哪个停车位没有被占用。
读取图像：
image
拿到图像之后，我们需要将其预处理，低于120，或者高于255的都处理为0。
def select_rgb_white_yellow(self,image):
#过滤掉背景
lower = np.uint8([120, 120, 120])
upper = np.uint8([255, 255, 255])
# lower_red和高于upper_red的部分分别变成0，lower_red～upper_red之间的值变成255,相当于过滤背景
white_mask = cv2.inRange(image, lower, upper)
self.cv_show('white_mask',white_mask)
masked = cv2.bitwise_and(image, image, mask = white_mask)
self.cv_show('masked',masked)
return masked
image
然后再将其与原始图像做与操作，这样的话，只有原始图像是255的像素点留下来了。
image
然后再做灰度处理，再做边缘检测：
image
手动选择有效区域：
def select_region(self,image):
"""
手动选择区域
"""
# first, define the polygon by vertices
rows, cols = image.shape[:2]
pt_1 = [cols*0.05, rows*0.90]
pt_2 = [cols*0.05, rows*0.70]
pt_3 = [cols*0.30, rows*0.55]
pt_4 = [cols*0.6, rows*0.15]
pt_5 = [cols*0.90, rows*0.15]
pt_6 = [cols*0.90, rows*0.90]
vertices = np.array([[pt_1, pt_2, pt_3, pt_4, pt_5, pt_6]], dtype=np.int32)
point_img = image.copy()
point_img = cv2.cvtColor(point_img, cv2.COLOR_GRAY2RGB)
for point in vertices[0]:
cv2.circle(point_img, (point[0],point[1]), 10, (0,0,255), 4)
self.cv_show('point_img',point_img)
return self.filter_region(image, vertices)
image
之后做一个mask填充，然后将其分割出来：
def filter_region(self,image, vertices):
"""
剔除掉不需要的地方
"""
mask = np.zeros_like(image)
if len(mask.shape)==2:
cv2.fillPoly(mask, vertices, 255)
self.cv_show('mask', mask)
return cv2.bitwise_and(image, mask)
image
image
再利用霍夫变换检测直线，再过滤一些：
def hough_lines(self,image):
#输入的图像需要是边缘检测后的结果
#minLineLengh(线的最短长度，比这个短的都被忽略)和MaxLineCap(两条直线之间的最大间隔，小于此值，认为是一条直线)
#rho距离精度,theta角度精度,threshod超过设定阈值才被检测出线段
return cv2.HoughLinesP(image, rho=0.1, theta=np.pi/10, threshold=15, minLineLength=9, maxLineGap=4)
def draw_lines(self,image, lines, color=[255, 0, 0], thickness=2, make_copy=True):
# 过滤霍夫变换检测到直线
if make_copy:
image = np.copy(image)
cleaned = []
for line in lines:
for x1,y1,x2,y2 in line:
if abs(y2-y1) <=1 and abs(x2-x1) >=25 and abs(x2-x1) <= 55:
cleaned.append((x1,y1,x2,y2))
cv2.line(image, (x1, y1), (x2, y2), color, thickness)
print(" No lines detected: ", len(cleaned))
return image
image
def identify_blocks(self,image, lines, make_copy=True):
if make_copy:
new_image = np.copy(image)
#Step 1: 过滤部分直线
cleaned = []
for line in lines:
for x1,y1,x2,y2 in line:
if abs(y2-y1) <=1 and abs(x2-x1) >=25 and abs(x2-x1) <= 55:
cleaned.append((x1,y1,x2,y2))
#Step 2: 对直线按照x1进行排序
import operator
list1 = sorted(cleaned, key=operator.itemgetter(0, 1))
#Step 3: 找到多个列，相当于每列是一排车
clusters = {}
dIndex = 0
clus_dist = 10
for i in range(len(list1) - 1):
distance = abs(list1[i+1][0] - list1[i][0])
if distance <= clus_dist:
if not dIndex in clusters.keys(): clusters[dIndex] = []
clusters[dIndex].append(list1[i])
clusters[dIndex].append(list1[i + 1])
else:
dIndex += 1
#Step 4: 得到坐标
rects = {}
i = 0
for key in clusters:
all_list = clusters[key]
cleaned = list(set(all_list))
if len(cleaned) > 5:
cleaned = sorted(cleaned, key=lambda tup: tup[1])
avg_y1 = cleaned[0][1]
avg_y2 = cleaned[-1][1]
avg_x1 = 0
avg_x2 = 0
for tup in cleaned:
avg_x1 += tup[0]
avg_x2 += tup[2]
avg_x1 = avg_x1/len(cleaned)
avg_x2 = avg_x2/len(cleaned)
rects[i] = (avg_x1, avg_y1, avg_x2, avg_y2)
i += 1
print("Num Parking Lanes: ", len(rects))
#Step 5: 把列矩形画出来
buff = 7
for key in rects:
tup_topLeft = (int(rects[key][0] - buff), int(rects[key][1]))
tup_botRight = (int(rects[key][2] + buff), int(rects[key][3]))
cv2.rectangle(new_image, tup_topLeft,tup_botRight,(0,255,0),3)
return new_image, rects
按列划分区域：
image
再划分更细：
image
之后再构建神经网络，对方框里面的图片进行分类。
image
完整代码 公众号后台回复 停车场车位识别 。
我的微信公众号名称：深度学习与先进智能决策
微信公众号ID：MultiAgent1024
公众号介绍：主要研究分享深度学习、机器博弈、强化学习等相关内容！期待您的关注，欢迎一起学习交流进步！