http://poj.org/problem?id=2251
很简单的求最短路径的BFS题目,才开始自己写了各DFS直接性TLE。。。
三维的,就是多加了两个方向罢了,再处理的时候就按i,j,k来;
#include <iostream> #include <cstring> #include <cstdio> #include <queue> #define maxn 33 using namespace std; struct node { int x,y,z; int len; }s; char map[maxn][maxn][maxn]; bool vt[maxn][maxn][maxn]; int l,r,c,ans; bool flag; int dir[6][3] = {{0,0,1},{0,0,-1},{0,1,0},{0,-1,0},{1,0,0},{-1,0,0}}; int bfs() { int i; node t; queue<node>q; while (!q.empty()) q.pop(); q.push(s); vt[s.x][s.y][s.z] = true; while (!q.empty()) { node cur = q.front(); q.pop(); if (map[cur.x][cur.y][cur.z] == 'E') { return cur.len; } for (i = 0; i < 6; ++i) { t.x = cur.x + dir[i][0]; t.y = cur.y + dir[i][1]; t.z = cur.z + dir[i][2]; if (t.x >= 0 && t.x < l && t.y >= 0 &&t.y < r && t.z >= 0 && t.z < c && map[t.x][t.y][t.z] != '#' && !vt[t.x][t.y][t.z]) { vt[t.x][t.y][t.z] = true; t.len = cur.len + 1; q.push(t); } } } return -1; } int main() { //freopen("in.txt","r",stdin); int i,j,k; while (scanf("%d%d%d",&l,&r,&c)) { if (!l && ! r && !c) break; for (i = 0; i < l; ++i) { for (j = 0; j < r; ++j) { scanf("%s",map[i][j]); for (k = 0; k < c; ++k) { if (map[i][j][k] == 'S') { s.x = i; s.y = j; s.z = k; s.len = 0; } } } } memset(vt,false,sizeof(vt)); int l = bfs(); if (l == -1) printf("Trapped!\n"); else printf("Escaped in %d minute(s).\n",l); } return 0; }