python实现zigzag_[Python](PAT)1127 ZigZagging on a Tree(30 分)

Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and inorder traversal sequences. And it is a simple standard routine to print the numbers in level-order. However, if you think the problem is too simple, then you are too naive. This time you are supposed to print the numbers in “zigzagging order” — that is, starting from the root, print the numbers level-by-level, alternating between left to right and right to left. For example, for the following tree you must output: 1 11 5 8 17 12 20 15.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤30), the total number of nodes in the binary tree. The second line gives the inorder sequence and the third line gives the postorder sequence. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print the zigzagging sequence of the tree in a line. All the numbers in a line must be separated by exactly one space, and there must be no extra space at the end of the line.

Sample Input:

8

12 11 20 17 1 15 8 5

12 20 17 11 15 8 5 1

1

2

3

4

8

1211201711585

1220171115851

Sample Output:

1 11 5 8 17 12 20 15

1

1115817122015

题目大意

给定一棵树的节点数以及中序遍历和后序遍历,要求输出这个树的”Z”型层序遍历。

分析

使用数组midd存储这颗树的中序遍历,使用数组post存储这颗树的后序遍历。使用bfs(midd, post)函数来层序遍历这颗树。

每次bfs函数获取post数组的最后一个元素,这个元素是这一段二叉树片段的根节点。在midd数组中找到根节点的位置,左边是左子树,右边是右子树。判断序列不为空则加入temp数组留待下一次层序遍历使用。将二叉树片段的根节点保存在now数组中,在while循环中判断当前是奇数层还是偶数层(从0开始)。偶数层反转now数组,奇数层不反转。将now数组加入result数组。继续下一次的层序遍历。

最后输出result数组即可

Python实现

Python实现

Python

def bfs(midd, post):

global result, temp, now

now.append(post[-1])

index = midd.index(post[-1])

if len(post[:index]) > 0:

temp.append([midd[:index], post[:index]])

if len(post[index:-1]) > 0:

temp.append([midd[index+1:], post[index:-1]])

if __name__ == "__main__":

num = int(input())

line = input().split(" ")

midd = [int(x) for x in line]

line = input().split(" ")

post = [int(x) for x in line]

result = []

a = [[midd, post]]

count = 0

while(len(a) > 0):

temp = []

now = []

for x in a:

bfs(x[0], x[1])

if count % 2 == 0:

result += now[::-1]

else:

result += now

count += 1

a = temp

result = [str(x) for x in result]

print(" ".join(result))

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defbfs(midd,post):

globalresult,temp,now

now.append(post[-1])

index=midd.index(post[-1])

iflen(post[:index])>0:

temp.append([midd[:index],post[:index]])

iflen(post[index:-1])>0:

temp.append([midd[index+1:],post[index:-1]])

if__name__=="__main__":

num=int(input())

line=input().split(" ")

midd=[int(x)forxinline]

line=input().split(" ")

post=[int(x)forxinline]

result=[]

a=[[midd,post]]

count=0

while(len(a)>0):

temp=[]

now=[]

forxina:

bfs(x[0],x[1])

ifcount%2==0:

result+=now[::-1]

else:

result+=now

count+=1

a=temp

result=[str(x)forxinresult]

print(" ".join(result))

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