Python 图片处理-图片翻转

 #coding=utf-8
 from PIL import Image
 import random
 def Jpg(dir_line):
   try:
    im=Image.open(dir_line)
   except IOError as er_info:
    print er_info
    exit()
   x=im.size[0]
   y=im.size[1]
   img=im.load()
   c = Image.new("RGB",(x,y))
   for i in range (0,x):
     for j in range (0,y):
        w=x-i-1
        h=y-j-1
        rgb=img[w,j] #镜像翻转
        rgb=img[w,h] #翻转180度
        rgv=img[i,h] #上下翻转
        c.putpixel([i,j],rgb)
   #90度的翻转实现
  ''''' y=im.size[0]
   x=im.size[1]
   img=im.load()
   c = Image.new("RGB",(x,y))
   for i in range (0,x):
     for j in range (0,y):
        w=x-i-1
        h=y-j-1
        rgb=img[j,i]#翻转90度
        c.putpixel([i,j],rgb)'''
   c.show()
   c.save("c.png")
 if __name__=="__main__":
   name="1.jpg"
   Jpg(name)
 原图:

镜像翻转：

转自：http://blog.csdn.net/reverseboy/article/details/45418305