通过opencv 读取图像将其保存为.bgr二进制格式文件

代码如下：

import os
import cv2
from numpy import *
import numpy as np
 

Img_dir = "～/cityscape_2048"  # 原图地址
Save_dir = "～/cityscape_images_2048" # 转成二进制的地址

def png2bgr(img_dir, save_dir):
    img = cv2.imread(img_dir)  # cv2 读取的图片本来就是bgr格式的，因此通过opencv转换非常方便
    shape = img.shape
    print(shape)  #  shape 是 [w, h, 3]
    #  使用一个元组收取BGR3通道的
    (B, G, R) = cv2.split(img)
    with open (save_dir, 'wb') as fp:
        for i in range(1024):
            for j in range(2048):
                fp.write(B[i, j])
                # print(B[i, j])
        for i in range(1024):
            for j in range(2048):
                fp.write(G[i, j])
                # print(G[i, j])
        for i in range(1024):
            for j in range(2048):
                fp.write(G[i, j])
                # print(G[i, j])

    print("write success!")
    
if __name__ == '__main__':
    count = 1
    for i in os.listdir(Img_dir):
        imdir = Img_dir+'/'+i
        save_dir = Save_dir+'/'+'{}.bgr'.format(count)
        png2bgr(imdir, save_dir)
        count+=1
        if count == 21:  # 这里我只需要20张即可
            print('convert over')
            break

转换之后就是.bgr文件