【PAT】甲级 A1053 Path of Equal Weight (30 分) (测试点6未通过求dl指点)

Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L.

Now given any weighted tree, you are supposed to find all the paths with their weights equal to a given number. For example, let’s consider the tree showed in the following figure: for each node, the upper number is the node ID which is a two-digit number, and the lower number is the weight of that node. Suppose that the given number is 24, then there exists 4 different paths which have the same given weight: {10 5 2 7}, {10 4 10}, {10 3 3 6 2} and {10 3 3 6 2}, which correspond to the red edges in the figure.
【PAT】甲级 A1053 Path of Equal Weight (30 分) (测试点6未通过求dl指点)_第1张图片

Input Specification:

Each input file contains one test case. Each case starts with a line containing 0

ID K ID[1] ID[2] … ID[K]

where ID is a two-digit number representing a given non-leaf node, K is the number of its children, followed by a sequence of two-digit ID’s of its children. For the sake of simplicity, let us fix the root ID to be 00.

Output Specification:

For each test case, print all the paths with weight S in non-increasing order. Each path occupies a line with printed weights from the root to the leaf in order. All the numbers must be separated by a space with no extra space at the end of the line.

Note: sequence {A1, A2, ⋯, An} is said to be greater than sequence {B1,B2,⋯,Bm } if there exists 1≤k Bk+1.​

Sample Input:

20 9 24
10 2 4 3 5 10 2 18 9 7 2 2 1 3 12 1 8 6 2 2
00 4 01 02 03 04
02 1 05
04 2 06 07
03 3 11 12 13
06 1 09
07 2 08 10
16 1 15
13 3 14 16 17
17 2 18 19

Sample Output:

10 5 2 7
10 4 10
10 3 3 6 2
10 3 3 6 2

我的代码如下:(存在问题)

#include
#include
#include
using namespace std;

const int maxn=110;
int path[maxn];
int n,m,s;//n为结点数,m为非叶子结点数,s为指定和
struct node{
	int data;
	vector<int> child;
}Node[maxn];

bool cmp(int a,int b){
	return Node[a].data>Node[b].data;
}
//index:当前访问结点 sum:当前和 
void DFS(int index,int num,int sum){
	int i;
	if(sum>s)
		return;
	if(sum==s&&Node[index].child.size()!=0)
		return;
	if(sum==s&&Node[index].child.size()==0){
		int i;
		for(i=0;i<num;i++){
			cout<<Node[path[i]].data;
			if(i<num-1)
				cout<<" ";
			else
				cout<<endl;
		}
		return;
	}
	for(i=0;i<Node[index].child.size();i++){
		int child=Node[index].child[i];
		path[num]=child;
		DFS(child,num+1,sum+Node[child].data);
	}
}

int main(){
	cin>>n>>m>>s;
	int i=0;
	for(i=0;i<n;i++){
		cin>>Node[i].data;
	}
	for(i=0;i<m;i++){
		int id,k;
		cin>>id>>k;
		int j;
		for(j=0;j<k;j++){
			int t;
			cin>>t;
			Node[id].child.push_back(t);
		}
		sort(Node[id].child.begin(),Node[id].child.end(),cmp);
	}
	path[0]=0;
	DFS(0,1,Node[0].data);
	return 0;
} 

然而测试点6没通过,这题只拿到29分…去网上搜了一下没有看到相关的内容,有没有大佬知道原因前来解惑qwq
【PAT】甲级 A1053 Path of Equal Weight (30 分) (测试点6未通过求dl指点)_第2张图片

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