deliphi 字符串分割_DELPHI 字符串分割处理

DELPHI 字符串分割处理

Code1

Function FindStr(BegSprStr,EdSpStr:String;varSource:String):String;2var3BegStr1Len,EdSpStr2Len,BegStr1Index,EdSpStr2index:integer;4Temp:String;5begin6Temp:=Source;7BegStr1Index:=Pos(BegSprStr,Temp);8BegStr1Len:=Length(BegSprStr);9delete(Temp,BegStr1Index,BegStr1Index+BegStr1Len-1);10EdSpStr2index:=Pos(EdSpStr,Temp);11EdSpStr2Len:=Length(EdSpStr);12Result:=Copy(Temp,1,EdSpStr2index-1);13Delete(Temp,1,EdSpStr2index+EdSpStr2Len-1);14Source:=temp;15end

該函數的功能就是取兩個相隔符之間的字符.

var Source:string

Source:=<1111>string1<1122><2233>string2<3344><4455>string3<5566>;

string1:=FindStr('<1111>','<1122>',Source);

String2:=FindStr('<2233>','<3344>',Source);

String3:=FindStr('<4455>','<5566>',Source);

//---------------------------------------------我想取得一个email地址的用户名

function myuser(email:string):string;

var

i,n:integer;

begin

n:=pos('@',email);

result:=copy(email,0,n-1);//改了一下

end;

//---------------------------------------------

下面就可以取出

leftstr(emaddress,Pos('@',emaddress))

//---------------------------------------------

uses IdGlobal;

User := Fetch(EmailAddress, '@');

//--------------------------------

ExtractStrings(要分隔的字符串，分隔字符串用的字符集合，分隔后排在第一位的消去的字符集合，字符串列表对象)

另一个函数SplitString

//这个我最喜欢用了

function SplitString(const source, ch: string): TStringList;

var

temp, t2: string;

i: integer;

begin

result := TStringList.Create;

temp := source;

i := pos(ch, source);

while i <> 0 do

begin

t2 := copy(temp, 0, i - 1);

if (t2 <> '') then

result.Add(t2);

delete(temp, 1, i - 1 + Length(ch));

i := pos(ch, temp);

end;

result.Add(temp);

end;

例子：

st := SplitString('[email protected]', '@');

则

st[0] = 'xxx';

st[1] = 'hoho.com';