说到递归查询,大家可以想到的技术实现方式主要如下几种:
1、各种主流应用开发语言本身通过算法实现
2、各种数据库引擎自身提供的算法实现
本文提到主要是针对第二种和第一种的结合
1、ORM:Mybatis
2、DB:MySQL
3、开发语言:Java
// dept_employee 员工和部门的关系表
// dept 部门信息表
// 根据员工编号查询其直属部门的所有下级部门节点
@Select({""})
List<Long> queryAllChildDeptByEmployeeId(@Param("employeeId") Long employeeId,@Param("type") String type);
// Mybatis Mapper类调用存储过程
@Select("call queryAllChildDeptByEmployeeId(#{employeeId},#{type})")
@Options(statementType = StatementType.CALLABLE)
List<Long> queryAllChildDeptByEmployeeId(@Param("employeeId") Long employeeId, String type);
//存储过程示例
CREATE DEFINER=`test`@`%` PROCEDURE `queryAllChildDeptByEmployeeId`(IN employeeId bigint,IN type VARCHAR(10))
BEGIN
if type is null or type ='' THEN
with recursive child_dept as
(
select id, code,name,name as dept_structure
from dept
where id in (
select DISTINCT dept_id from dept_employee
where employee_id= employeeId
)
union
select a.id,a.code ,a.name, concat(b.dept_structure, ' > ', a.name) as dept_structure
from child_dept as b
join dept as a on b.code=a.parent_code
)
select DISTINCT id from child_dept;
ELSE
with recursive child_dept as
(
select id, code,name,name as dept_structure
from dept
where id in (
select DISTINCT dept_id from dept_employee
where employee_id= employeeId and type=type
)
union
select a.id,a.code ,a.name, concat(b.dept_structure, ' > ', a.name) as dept_structure
from child_dept as b
join dept as a on b.code=a.parent_code
)
select DISTINCT id from child_dept;
END IF;
END
以上实现方式涉及到了MySQL的with as 语法,此实现方式必须给予MySQL 8.0.x版本,5.x.x版本不支持,
解决方案:
1、升级数据库版本为8.x版本
2、采用5.x版本语法FIND_IN_SET,如下代码示例
SELECT au.id, au.name, au.pid
FROM (SELECT * FROM dept WHERE pid IS NOT NULL) au,
(SELECT @pid := '1002,1005') pd
WHERE FIND_IN_SET(pid, @pid) > 0 and @pid := concat(@pid, ',', id)
UNION
SELECT id, name, pid
FROM dept
WHERE FIND_IN_SET(id, @pid) > 0
ORDER BY id;
3、采用应用开发语言实现,如Java代码实现