<statement id="degreeretrive" parameterClass="Hashtable" resultClass="Degree"> select * from Degree where Account_id = #Account_ID# </statement>
<select id="GetComTables" resultMap="comresult"> select * from Accounts order by Account_ID </select>
这样可以正确的查询出结果,符合OO,但是也有两个小问题:
1、比较麻烦,不够灵活
2、性能受影响:
这种方式其实和Hibernet比较类似了,查询时首先执行
select * from Accounts order by Account_ID 然后根据这条语句的结果,比如有100条记录,那就要执行100次以下的语句:
select * from Degree where Account_id = @param0
Traits are a fundamental unit of code reuse in Scala. A trait encapsulates method and field definitions, which can then be reused by mixing them into classes. Unlike class inheritance, in which each c
版本:WebLogic Server 10.3
说明:%DOMAIN_HOME%:指WebLogic Server 域(Domain)目录
例如我的做测试的域的根目录 DOMAIN_HOME=D:/Weblogic/Middleware/user_projects/domains/base_domain
1.为了保证操作安全,备份%DOMAIN_HOME%/security/Defa
http://crazyjvm.iteye.com/blog/1693757 文中提到相关超时问题,但是又出现了一个问题,我把min和max都设置成了180000,但是仍然出现了以下的异常信息:
Client session timed out, have not heard from server in 154339ms for sessionid 0x13a3f7732340003
在Mysql 众多表中查找一个表名或者字段名的 SQL 语句:
方法一:SELECT table_name, column_name from information_schema.columns WHERE column_name LIKE 'Name';
方法二:SELECT column_name from information_schema.colum