python找出列表里大于输出,python找出列表中大于某个阈值的数据段
该算法实现对列表中大于某个阈值(比如level=5)的连续数据段的提取，具体效果如下：
找出list里面大于5的连续数据段：
list = [1,2,3,4,2,3,4,5,6,7,4,6,7,8,5,6,7,3,2,4,4,4,5,3,6,7,8,9,8,6,1]
输出：
[[6, 7], [6, 7, 8], [6, 7], [6, 7, 8, 9, 8, 6]]
算法实现：
# -*- coding: utf-8 -*-
"""
--------------------------------------------------------
# @Version : python3.6
# @Author : wtg
# @File : data_search.py
# @Software: PyCharm
# @Time : 2018/12/17 14:44
--------------------------------------------------------
# @Description:
--------------------------------------------------------
"""
def data_search(data, level):
list = []
temp = []
for i in range(len(data)):
if data[i] > level:
temp.append(data[i])
else:
list.append(temp)
temp = []
return [i for i in list if i]
if __name__ == '__main__':
list = [1,2,3,4,2,3,4,5,6,7,4,6,7,8,5,6,7,3,2,4,4,4,5,3,6,7,8,9,8,6,1]
ret = data_search(list, 5)
print("input: ",list)
print("output: ",ret)
效果如下：