A cryptarithm is a mathematical puzzle for which the goal is to find the correspondence between letters and digits, such that the given arithmetic equation consisting of letters holds true when the letters are converted to digits.
You have an array of strings crypt
, the cryptarithm, and an an array containing the mapping of letters and digits, solution
. The array crypt
will contain three non-empty strings that follow the structure: [word1, word2, word3]
, which should be interpreted as the word1 + word2 = word3
cryptarithm.
If crypt
, when it is decoded by replacing all of the letters in the cryptarithm with digits using the mapping in solution
, becomes a valid arithmetic equation containing no numbers with leading zeroes, the answer is true
. If it does not become a valid arithmetic solution, the answer is false
.
Note that number 0
doesn't contain leading zeroes (while for example 00
or 0123
do).
Example
For crypt = ["SEND", "MORE", "MONEY"]
and
solution = [['O', '0'],
['M', '1'],
['Y', '2'],
['E', '5'],
['N', '6'],
['D', '7'],
['R', '8'],
['S', '9']]
the output should besolution(crypt, solution) = true
.
When you decrypt "SEND"
, "MORE"
, and "MONEY"
using the mapping given in crypt
, you get 9567 + 1085 = 10652
which is correct and a valid arithmetic equation.
For crypt = ["TEN", "TWO", "ONE"]
and
solution = [['O', '1'],
['T', '0'],
['W', '9'],
['E', '5'],
['N', '4']]
the output should besolution(crypt, solution) = false
.
Even though 054 + 091 = 145
, 054
and 091
both contain leading zeroes, meaning that this is not a valid solution.
Input/Output
[execution time limit] 4 seconds (py3)
[memory limit] 1 GB
[input] array.string crypt
An array of three non-empty strings containing only uppercase English letters.
Guaranteed constraints:crypt.length = 3
,1 ≤ crypt[i].length ≤ 14
.
[input] array.array.char solution
An array consisting of pairs of characters that represent the correspondence between letters and numbers in the cryptarithm. The first character in the pair is an uppercase English letter, and the second one is a digit in the range from 0
to 9
.
It is guaranteed that solution
only contains entries for the letters present in crypt
and that different letters have different values.
Guaranteed constraints:solution[i].length = 2
,'A' ≤ solution[i][0] ≤ 'Z'
,'0' ≤ solution[i][1] ≤ '9'
,solution[i][0] ≠ solution[j][0], i ≠ j
,solution[i][1] ≠ solution[j][1], i ≠ j
.
[output] boolean
Return true
if the solution
represents the correct solution to the cryptarithm crypt
, otherwise return false
.
def solution(crypt, solution):
mapping = {}
for pair in solution:
mapping[pair[0]] = pair[1]
decrypted = []
for word in crypt:
decrypted_word = ''
for letter in word:
decrypted_word += mapping[letter]
decrypted.append(decrypted_word)
if any(word.startswith('0') and len(word) > 1 for word in decrypted):
return False
decrypted_nums = list(map(int, decrypted))
return decrypted_nums[0] + decrypted_nums[1] == decrypted_nums[2]