1、删除表employee:
drop table employee;
2、创建表emp:
3、添加数据:
4、查看表数据:
【代码】
-- 查询数据---------------------------------------------------------
drop table emp;
-- 数据准备---------------------------------------------------------
create table emp(
id int comment '编号',
workno varchar(10) comment '工号',
name varchar(10) comment '姓名',
gender char(1) comment '性别',
age tinyint unsigned comment '年龄',
idcard char(18) comment '身份证号',
workaddress varchar(50) comment '工作地址',
entrydate date comment '入职时间'
) comment '员工表';
insert into emp (id, workno, name, gender, age, idcard, workaddress, entrydate)
VALUES (1, '1', '柳岩', '女', 20, '123456789012345601', '北京', '2000-01-01'),
(2, '2', '张无忌', '男', 18, '123456789012345602', '北京', '2005-09-02'),
(3, '3', '韦一笑', '男', 38, '123456789012345603', '北京', '2005-08-03'),
(4, '4', '赵敏', '女', 18, '123456789012345604', '武汉', '2009-12-04'),
(5, '5', '小昭', '女', 16, '123456789012345605', '武汉', '2007-07-05'),
(6, '6', '杨逍', '男', 28, '12345678901234560X', '北京', '2006-01-06'),
(7, '7', '范瑶', '男', 40, '123456789012345607', '天津', '2005-05-07'),
(8, '8', '黛绮丝', '女', 38, '123456789012345608', '天津', '2015-05-08'),
(9, '9', '范冰冰', '女', 45, '123456789012345609', '淄博', '2010-04-09'),
(10, '10', '陈友谅', '男', 53, '123456789012345610', '淄博', '2011-01-10'),
(11, '11', '张士诚', '男', 55, '123456789012345611', '北京', '2015-05-11'),
(12, '12', '常遇春', '男', 32, '123456789012345612', '武汉', '2004-02-12'),
(13, '13', '张三', '男', 88, '123456789012345613', '天津', '2020-11-13'),
(14, '14', '灭绝', '女', 65, '123456789012345614', '天津', '2019-05-14'),
(15, '15', '胡青牛', '男', 70, '12345678901234561X', '淄博', '2018-04-15'),
(16, '16', '周芷若', '女', 18, null , '天津', '2012-06-16');
select name, workno, age from emp;
执行后效果:
select id, workno, name, gender, age, idcard, workaddress, entrydate from emp;
-- 虽然效果一样,都是查询所有字段,但是尽量不要用*,不直观,也不规范
select * from emp;
执行后效果:
(1)查询所有员工的工作地址
select workaddress from emp;
(2)起别名
workaddress可读性不强,起个别名“工作”地址,代码:
select workaddress as '工作地址' from emp;
-- as可以省略,效果一样
select workaddress '工作地址' from emp;
select distinct workaddress '工作地址' from emp;