1002:方便记忆的电话号码

这道题模拟即可，几点注意：

1. 使用Map用TreeMap， 自带排序功能以减少使用Heap
2. 补齐0不要用String.format太慢

import java.util.Scanner;
import java.util.TreeMap;

public class Main {
    static int[] table = {2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,0,7,7,8,8,8,9,9,9,0};
    static String[] leadingZero= {"000000", "00000", "0000", "000", "00", "0", ""};
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int N = scanner.nextInt();
        scanner.nextLine();

        TreeMap map = new TreeMap<>();

        for (int i = 0; i < N; ++i) {
            String raw = scanner.nextLine();
            int val = getNumber(raw);
            if (map.containsKey(val)) {
                map.replace(val, map.get(val) + 1);
            } else {
                map.put(val, 1);
            }
        }

        boolean flag = false;
        for (Integer x : map.keySet()) {
            int y = map.get(x);
            if (y > 1) {
                flag = true;
                String s = String.valueOf(x);
                s = leadingZero[s.length() - 1] + s;
                System.out.println(s.substring(0, 3) + '-' + s.substring(3, 7) + " " + y);
            }
        }

        if (!flag) System.out.println("No duplicates.");
    }

    static int getNumber (String raw) {
        int res = 0;
        for (int i = 0; i < raw.length(); ++i) {
            char ch = raw.charAt(i);
            if (ch == '-') continue;
            if (Character.isDigit(ch)) {
                res = res * 10 + (ch - '0');
            } else {
                res = res * 10 + table[ch - 'A'];
            }
        }
        return res;
    }
}

以下是错误示范
TLE

import java.util.HashMap;
import java.util.PriorityQueue;
import java.util.Scanner;

public class Main {
    static char[] table = {'2','2','2','3','3','3','4','4','4','5','5','5','6','6','6','7','0','7','7','8','8','8','9','9','9','0'};

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int N = scanner.nextInt();
        scanner.nextLine();
        HashMap map = new HashMap<>();
        PriorityQueue queue = new PriorityQueue<>();

        for (int i = 0; i < N; ++i) {
            String s = getNumber(scanner.nextLine());
            if (map.containsKey(s)) {
                map.replace(s, map.get(s) + 1);
            } else {
                map.put(s, 1);
                queue.add(s);
            }
        }

        if (queue.size() == N) {
            System.out.println("No duplicates.");
        } else {
            while (!queue.isEmpty()) {
                String s = queue.poll();
                int k = map.get(s);
                if (k >= 2)
                    System.out.println(s + " " + map.get(s));
            }
        }
    }
    private static String getNumber(String raw) {

        char[] seq = new char[8];

        int t = 0;

        for (int i = 0; i < raw.length(); ++i) {

            char ch = raw.charAt(i);

            if (ch == '-') continue;

            if (Character.isLetter(ch)) {
                seq[t++] = table[ch - 'A'];
            } else {
                seq[t++] = ch;
            }

            if (t == 3) seq[t++] = '-';
        }

        return String.valueOf(seq);
    }
}

Runtime Error (The array might be too large)

import java.util.Scanner;

public class Main {
    static int[] table = {2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,0,7,7,8,8,8,9,9,9,0};
    static int[] count = new int[7777779];
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int N = scanner.nextInt();
        scanner.nextLine();

        for (int i = 0; i < N; ++i) {
            int x = 0;
            String raw = scanner.nextLine();
            for (int j = 0; j < raw.length(); ++j) {
                char ch = raw.charAt(j);
                if (ch == '-') continue;
                if (Character.isLetter(ch)) {
                    x = x * 10 + table[ch - 'A'];
                } else {
                    x = x * 10 + (ch - '0');
                }
            }
            ++count[x - 2222222];
        }

        boolean flag = false;
        for (int i = 0; i < count.length; ++i) {
            if (count[i] >= 2) {
                int pos = i + 2222222;
                StringBuffer buffer = new StringBuffer(String.valueOf(pos));
                buffer.insert(3, "-");
                System.out.println(buffer.toString() + " " + count[i]);
                flag = true;
            }
        }
        if (!flag) {
            System.out.println("No duplicates.");
        }
    }

    static String getFormatNumber (int pos) {
        pos += 2222222;
        StringBuffer buffer = new StringBuffer(String.valueOf(pos));
        buffer.insert(3, "-");
        return buffer.toString();
    }
}