JSON与String字符串相互转换的方法

首先创建一个简单的类

package com.wei.demo.pojo;

/**
 * @Author wei
 * @Date 2022/6/2 9:24
 * @Version 1.0
 */
public class Teacher {

    private int id;

    private String name;

    private int age;

    public Teacher() {
    }

    public Teacher(int id, String name, int age) {
        this.id = id;
        this.name = name;
        this.age = age;
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }

    @Override
    public String toString() {
        return "Teacher{" +
                "id=" + id +
                ", name='" + name + '\'' +
                ", age=" + age +
                '}';
    }
}

备注：我这里使用的是maven仓库

1、 使用ObjectMapper类进行转换

需要导入依赖，可以选择导入以下依赖

不过我不喜欢这样，如果可以用一个依赖包括这些就好了，所以我选择导入这个依赖

		<dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
            <version>2.5.0</version>
        </dependency>

这一个依赖里面包含了上面的几个依赖

这样更方便一点。
接下来直接进行测试

测试如下：

package com.wei.demo.pojo;

import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;

/**
 * @Author wei
 * @Date 2022/6/2 9:25
 * @Version 1.0
 */
public class Test {

    public static void main(String[] args) throws JsonProcessingException {

        ObjectMapper mapper = new ObjectMapper();

        Teacher teacher = new Teacher(1, "张三", 25);

        String teachStr = mapper.writeValueAsString(teacher);

        System.out.println("转换为字符串为：" + teachStr);

        Teacher teachValue = mapper.readValue(teachStr, Teacher.class);

        System.out.println("转换为teacher字符为："+ teachValue.toString());



    }
}

这里需要注意的是：在Teacher类里面需要创建一个无参构造，否则会报错

2、使用阿里巴巴的fastJSON来进行转换

1、导入依赖

<dependency>
            <groupId>com.alibaba</groupId>
            <artifactId>fastjson</artifactId>
            <version>1.2.76</version>
        </dependency>

2、测试

package com.wei.demo.pojo;

import com.alibaba.fastjson.JSON;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;

/**
 * @Author wei
 * @Date 2022/6/2 9:25
 * @Version 1.0
 */
public class Test1 {

    public static void main(String[] args) {

        Teacher teacher = new Teacher(1, "张三", 25);

        String teachStr = JSON.toJSONString(teacher);

        System.out.println("转换为字符串为：" + teachStr);

        Teacher teachValue = JSON.parseObject(teachStr, Teacher.class);

        System.out.println("转换为teacher字符为："+ teachValue.toString());
    }
}

这两种方法都可以转换