function brussode(N)
%BRUSSODE Stiff problem modelling a chemical reaction (the Brusselator).
% The parameter N >= 2 is used to specify the number of grid points; the
% resulting system consists of 2N equations. By default, N is 20. The
% problem becomes increasingly stiff and increasingly sparse as N is
% increased. The Jacobian for this problem is a sparse constant matrix
% (banded with bandwidth 5).
%
% The property 'JPattern' is used to provide the solver with a sparse
% matrix of 1's and 0's showing the locations of nonzeros in the Jacobian
% df/dy. By default, the stiff solvers of the ODE Suite generate Jacobians
% numerically as full matrices. However, when a sparsity pattern is
% provided, the solver uses it to generate the Jacobian numerically as a
% sparse matrix. Providing a sparsity pattern can significantly reduce the
% number of function evaluations required to generate the Jacobian and can
% accelerate integration. For the BRUSSODE problem, only 4 evaluations of
% the function are needed to compute the 2N x 2N Jacobian matrix.
%
% Setting the 'Vectorized' property indicates the function f is
% vectorized.
%
% E. Hairer and G. Wanner, Solving Ordinary Differential Equations II,
% Stiff and Differential-Algebraic Problems, Springer-Verlag, Berlin,
% 1991, pp. 5-8.
%
% See also ODE15S, ODE23S, ODE23T, ODE23TB, ODESET, FUNCTION_HANDLE.
% Mark W. Reichelt and Lawrence F. Shampine, 8-30-94
% Copyright 1984-2014 The MathWorks, Inc.
% Problem parameter, shared with the nested function.
if nargin<1
N = 20;
end
tspan = [0; 10];
y0 = [1+sin((2*pi/(N+1))*(1:N)); repmat(3,1,N)];
options = odeset('Vectorized','on','JPattern',jpattern(N));
[t,y] = ode15s(@f,tspan,y0,options);
u = y(:,1:2:end);
x = (1:N)/(N+1);
figure;
surf(x,t,u);
view(-40,30);
xlabel('space');
ylabel('time');
zlabel('solution u');
title(['The Brusselator for N = ' num2str(N)]);
% -------------------------------------------------------------------------
% Nested function -- N is provided by the outer function.
%
function dydt = f(t,y)
% Derivative function
c = 0.02 * (N+1)^2;
dydt = zeros(2*N,size(y,2)); % preallocate dy/dt
% Evaluate the 2 components of the function at one edge of the grid
% (with edge conditions).
i = 1;
dydt(i,:) = 1 + y(i+1,:).*y(i,:).^2 - 4*y(i,:) + c*(1-2*y(i,:)+y(i+2,:));
dydt(i+1,:) = 3*y(i,:) - y(i+1,:).*y(i,:).^2 + c*(3-2*y(i+1,:)+y(i+3,:));
% Evaluate the 2 components of the function at all interior grid points.
i = 3:2:2*N-3;
dydt(i,:) = 1 + y(i+1,:).*y(i,:).^2 - 4*y(i,:) + ...
c*(y(i-2,:)-2*y(i,:)+y(i+2,:));
dydt(i+1,:) = 3*y(i,:) - y(i+1,:).*y(i,:).^2 + ...
c*(y(i-1,:)-2*y(i+1,:)+y(i+3,:));
% Evaluate the 2 components of the function at the other edge of the grid
% (with edge conditions).
i = 2*N-1;
dydt(i,:) = 1 + y(i+1,:).*y(i,:).^2 - 4*y(i,:) + c*(y(i-2,:)-2*y(i,:)+1);
dydt(i+1,:) = 3*y(i,:) - y(i+1,:).*y(i,:).^2 + c*(y(i-1,:)-2*y(i+1,:)+3);
end
% -------------------------------------------------------------------------
end % brussode
% ---------------------------------------------------------------------------
% Subfunction -- the sparsity pattern
%
function S = jpattern(N)
% Jacobian sparsity pattern
B = ones(2*N,5);
B(2:2:2*N,2) = zeros(N,1);
B(1:2:2*N-1,4) = zeros(N,1);
S = spdiags(B,-2:2,2*N,2*N);
end
% ---------------------------------------------------------------------------
通过运行函数 brussode,对N=20时的 Brusselator 方程组求解。
brussode
通过为 brussode 指定输入,对N=50时的方程组求解。
brussode(50)