Java使用正则表达式校验格式

 正则表达式校验文本格式

        final String regex = "^([1-9]\\d{3})-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (0?\\d|1\\d|2[0-3]):([0-5]\\d):([0-5]\\d)$";
        final String string = "2022-10-18 13:33:33";
        final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
        final Matcher matcher = pattern.matcher(string);
        System.out.println(matcher.matches());

        //或者使用
        Pattern.matches(regex, string)

        //或者使用
        System.out.println(string.matches(regex));

过滤文本类型

提取汉字 

str.replaceAll("\\s*","").replaceAll("[^(\\u4e00-\\u9fa5)]","")

 提取字母

str.replaceAll("\\s*","").replaceAll("[^(A-Za-z)]","")

 提取数字

str.replaceAll("\\s*","").replaceAll("[^(a-zA-Z0-9)]","")

数字+字母

str.replaceAll("\\s*","").replaceAll("[^(a-zA-Z0-9)]","")

 过滤空字符串

        //去掉首尾空格
        System.out.println("去掉首尾空格:" + str1.trim());
        //去掉所有空格
        System.out.println("去掉所有空格:" + str2.replace(" ",""));
        System.out.println("去掉所有空格:" + str3.replaceAll(" ",""));
        System.out.println("去掉所有空格:" + str4.replaceAll(" +",""));
        //去掉特殊的空格、制表符、换页符
        System.out.println("去掉特殊的空格、制表符、换页符:" + str5.replaceAll("\\s*",""));

空字符串分割

\s匹配任何空白字符,包括空格、制表符、换页符等等, 等价于[ \f\n\r\t\v]

\f 匹配一个换页

\n匹配一个换行符

\r匹配一个回车符

\t匹配一个制表符

\v匹配一个垂直制表符

而“\s+”则表示匹配任意多个上面的字符。

另因为反斜杠在Java里是转义字符,所以在Java里,我们要这么用:str.split("\\s+");

[\S]表示,非空白就匹配

常用正则表达式:

数字校验(包含负数)

-?[0-9]+(.[0-9]+)?

有效时间(00:00-23:59)

^(20|21|22|23|[0-1]\d):[0-5]\d-(20|21|22|23|[0-1]\d):[0-5]\d$

 验证密码(大写字母、小写字母、数字、特殊字符中三种或三种以上的组合,长度自定)

String regex = "^(?![a-zA-Z]+$)(?![A-Z0-9]+$)(?![A-Z\\W]+$)(?![a-z0-9]+$)(?![a-z\\W]+$)(?![0-9\\W]+$)[a-zA-Z0-9_\\W]*"
            + pwdThMin + "," + pwdThMax + "}$";

IP验证 

^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$
^((25[0-5]|2[0-4]\d|((1\d{2})|([1-9]?\d)))\.){3}(25[0-5]|2[0-4]\d|((1\d{2})|([1-9]?\d)))$

 端口验证

^([0-9]|[1-9]\d{1,3}|[1-5]\d{4}|6[0-4]\d{4}|65[0-4]\d{2}|655[0-2]\d|6553[0-5])$

IP+端口验证

^((?:(?:\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])(?:\.(?!\:)|)){4})\:(?!0)(\d{1,4}|[1-5]\d{4}|6[0-4]\d{3}|65[0-4]\d{2}|655[0-2]\d|6553[0-5])$

MAC地址验证

^([0-9a-fA-F]{2})(([/\s:][0-9a-fA-F]{2}){5})$

                         与(|)

^([0-9a-fA-F]{2})(([/\s-][0-9a-fA-F]{2}){5})$

手机号验证

(\+\d+)?1[345789]\d{9}$

网址验证

((([A-Za-z]{3,9}:(?:\/\/)?)(?:[-;:&=\+\$,\w]+@)?[A-Za-z0-9.-]+|(?:www.|[-;:&=\+\$,\w]+@)[A-Za-z0-9.-]+)((?:\/[\+~%\/.\w-_]*)?\??(?:[-\+=&;%@.\w_]*)#?(?:[.\!\/\\w]*))?)

JSON验证

/(?(DEFINE)
# Note that everything is atomic, JSON does not need backtracking if it's valid
# and this prevents catastrophic backtracking
(?(?>\s*(?&object)\s*|\s*(?&array)\s*))
(?(?>\{\s*(?>(?&pair)(?>\s*,\s*(?&pair))*)?\s*\}))
(?(?>(?&STRING)\s*:\s*(?&value)))
(?(?>\[\s*(?>(?&value)(?>\s*,\s*(?&value))*)?\s*\]))
(?(?>true|false|null|(?&STRING)|(?&NUMBER)|(?&object)|(?&array)))
(?(?>"(?>\\(?>["\\\/bfnrt]|u[a-fA-F0-9]{4})|[^"\\\0-\x1F\x7F]+)*"))
(?(?>-?(?>0|[1-9][0-9]*)(?>\.[0-9]+)?(?>[eE][+-]?[0-9]+)?))
)
\A(?&json)\z/x 
  

1-15 个字母数字登录名

^(?=.*[a-zA-Z]{1,})(?=.*[\d]{0,})[a-zA-Z0-9]{1,15}$

邮箱验证

^([\w-]+(?:\.[\w-]+)*)@((?:[\w-]+\.)*\w[\w-]{0,66})\.([a-z]{2,6}(?:\.[a-z]{2})?)$

替换文本中的日期 

  /**
     * 替换文本中日期
     *
     * @param content 字符串
     * @param date 替换的日期
     * @return
     */
    public String dateOfReplacement(String content, String date) {
        Pattern p = Pattern.compile("(\\d{4})-(\\d{1,2})-(\\d{1,2}) (\\d{1,2}):(\\d{1,2}):(\\d{1,2})");
        Matcher matcher = p.matcher(content);
        while (matcher.find()) {
            String group = matcher.group(0);
            return content.replace(group, date);
        }
        return content;
    }

 

 

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