| 4.1计算每月总收入 4.2计算每个季度的总收入 4.3按年计算总收入 4.4按工作日计算总收入 4.5按时间段计算总收入(需要清理数据) 4.6按时间段计算平均消费 4.4按工作日计算平均消费 4.8计算年、月、日的交易总数 4.9找出交易量最大的10个客户 4.10找出消费最多的前10位顾客 -- 1计算每月总收入
select
purchase_month, sum(price) as monthSUM
from transaction_details
group by purchase_month;
-- 2计算每季度总收入
with
base as ( select
price,
concat_ws('-',substr(purchase_date,1,4),cast(ceil(month(purchase_date)/3.0) as string))as year_quarter
from transaction_details)
select year_quarter, sum(price) as year_quarterSUM from base group by year_quarter;
-- 3计算每年度总收入
select
substr(purchase_date,1,4),
sum(price) as yearSUM
from transaction_details
group by substr(purchase_date,1,4);
-- 4计算工作日收入
select
`dayofweek`(purchase_date),
sum(price) as daySUM
from transaction_details
group by `dayofweek`(purchase_date)
having `dayofweek`(purchase_date) in (2,3,4,5,6);
-- 5按时间段计算总收入(需要清理数据)
with
base as (
select price,purchase_time,
if(purchase_time like '%M',from_unixtime(unix_timestamp(purchase_time,'hh:mm aa'),'HH:mm'),purchase_time) as time_format
from transaction_details),
timeformat as (
select price, purchase_time, time_format, (cast(split(time_format,':')[0] as decimal(4,2))+ cast(split(time_format,':')[1] as decimal(4,2))/60) as purchase_time_in_hr from base),
t1 as (select price, purchase_time, time_format, purchase_time_in_hr,
`if`(purchase_time_in_hr > 5 and purchase_time_in_hr <= 8, 'early morning',
`if`(purchase_time_in_hr > 8 and purchase_time_in_hr <= 11, 'morning',
`if`(purchase_time_in_hr > 11 and purchase_time_in_hr <= 13, 'noon',
`if`(purchase_time_in_hr > 13 and purchase_time_in_hr <= 18, 'afternoon',
`if`(purchase_time_in_hr > 18 and purchase_time_in_hr <= 22, 'evening', 'night'))))) as time_bucket
from timeformat)
select time_bucket, sum(price) bucketSUM, avg(price) avgprice from t1 group by time_bucket ;
-- 6按时间段计算平均消费
-- 7按工作日计算平均消费
select
`dayofweek`(purchase_date),
avg(price) as dayAVG
from transaction_details
where `dayofweek`(purchase_date) in (2,3,4,5,6)
group by `dayofweek`(purchase_date);
-- 8计算年、月、日的交易总数
select
year(purchase_date) currentYear,
count(1) as sumCount
from transaction_details
group by year(purchase_date);
select
substring(purchase_date,1,7) currentMonth,
count(1) as sumCount
from transaction_details
group by substring(purchase_date,1,7);
select
day(purchase_date) currentDay,
count(1) as sumCount
from transaction_details
group by day(purchase_date);
-- 9找出交易量最大的10个客户
with
base as (
select customer_id,count(transaction_id) as trans_cnt,sum(price) as customerSUM from transaction_details group by customer_id),
cust_detail as(
select concat_ws(' ', cd.first_name, '***') as cust_name, base.* ,
dense_rank() over (order by trans_cnt desc ) rn from base join vw_customer_details cd on base.customer_id=cd.customer_id)
select * from cust_detail where rn<=10;
-- 10找出消费最多的前10位顾客
with
base as (
select customer_id,sum(price) as customerSUM from transaction_details group by customer_id),
cust_detail as(
select concat_ws(' ', cd.first_name, '***') as cust_name, base.* ,
dense_rank() over (order by customerSUM desc ) rn from base join vw_customer_details cd on base.customer_id=cd.customer_id)
select * from cust_detail where rn<=10;
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| Mysql中建表查询 7.11统计该期间交易数量最少的用户 7.12计算每个季度的独立客户总数 7.13计算每周的独立客户总数 7.14计算整个活动客户平均花费的最大值 7.15统计每月花费最多的客户 7.16统计每月访问次数最多的客户 7.17按总价找出最受欢迎的5种产品 7.18根据购买频率找出最畅销的5种产品 7.19根据客户数量找出最受欢迎的5种产品 -- 7.11统计该期间交易数量最少的用户
WITH
t1 AS(SELECT customer_id,COUNT(1) c FROM transaction_details GROUP BY customer_id ORDER BY c),
t2 AS(SELECT t1.*,DENSE_RANK() over(ORDER BY t1.c) as rn FROM t1)
SELECT CONCAT(vcd.first_name,'***'), t2.* FROM t2 JOIN vw_customer_details vcd ON t2.customer_id=vcd.customer_id WHERE rn=1;
-- 7.12计算每个季度的独立客户总数
SELECT DISTINCT COUNT(customer_id),
concat_ws('-',substr(purchase_date,1,4),cast(ceil(month(purchase_date)/3.0) as CHAR(20)))as year_quarter
from transaction_details
GROUP BY year_quarter
ORDER BY (year_quarter+0);
-- 7.13计算每周的独立客户总数
SELECT DISTINCT COUNT(customer_id),
concat_ws('-',substr(purchase_date,1,4),cast(WEEKOFYEAR(purchase_date) as CHAR(20)))as week_year
from transaction_details
GROUP BY week_year;
-- 7.14计算整个活动客户平均花费的最大值
WITH
t1 AS(SELECT customer_id, avg(price) as costAVG FROM transaction_details GROUP BY customer_id),
t2 AS(SELECT t1.*,DENSE_RANK() over(ORDER BY costAVG DESC) as rn FROM t1)
SELECT * FROM t2 WHERE rn=1;
-- 7.15统计每月花费最多的客户
WITH
t1 AS(SELECT purchase_month,customer_id, sum(price) as costSUM FROM transaction_details GROUP BY purchase_month,customer_id),
t2 AS(SELECT t1.*,DENSE_RANK() over(PARTITION by purchase_month ORDER BY costSUM DESC) as rn FROM t1)
SELECT CONCAT(vcd.first_name,'***'), t2.* FROM t2 JOIN vw_customer_details vcd ON t2.customer_id=vcd.customer_id WHERE rn=1;
-- 7.16统计每月访问次数最多的客户
WITH
t1 AS(SELECT purchase_month,customer_id, count(customer_id) as costCount FROM transaction_details GROUP BY purchase_month,customer_id),
t2 AS(SELECT t1.*,DENSE_RANK() over(PARTITION by purchase_month ORDER BY costCount DESC) as rn FROM t1)
SELECT CONCAT(vcd.first_name,'***'), t2.* FROM t2 JOIN vw_customer_details vcd ON t2.customer_id=vcd.customer_id WHERE rn=1;
-- 7.17按总价找出最受欢迎的5种产品
WITH
t1 AS(SELECT product,sum(price) as proSUM FROM transaction_details GROUP BY product),
t2 AS(SELECT t1.*,DENSE_RANK() over(ORDER BY proSUM DESC) as rn FROM t1)
SELECT * FROM t2 WHERE rn BETWEEN 1 AND 5;
-- 7.18根据购买频率找出最畅销的5种产品
WITH
t1 AS(SELECT product,COUNT(product) as proCount FROM transaction_details GROUP BY product),
t2 AS(SELECT t1.*,DENSE_RANK() over(ORDER BY proCount DESC) as rn FROM t1)
SELECT * FROM t2 WHERE rn BETWEEN 1 AND 5;
-- 7.19根据客户数量找出最受欢迎的5种产品
WITH
t1 AS(SELECT product,COUNT(customer_id) as proCount FROM transaction_details GROUP BY product),
t2 AS(SELECT t1.*,DENSE_RANK() over(ORDER BY proCount DESC) as rn FROM t1)
SELECT * FROM t2 WHERE rn BETWEEN 1 AND 5;
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